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3 years ago

(-2) + (-4) - 8 x ( 2 ÷ ( (-10) ÷ 10) ) Please show work!

Mathematics

2 answers:

labwork [276]3 years ago

6 0

Answer:

the answer is attached to the picture

frozen [14]3 years ago

4 0

Answer:

$10$

hope this helps

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Find the compound interest compounded annually on rupees 2700 rate 6 ⅔% per annum and time is 2 years

dalvyx [7]

Answer:

plz mark me as brainliest ...TOOK ME LONG TIME TO TYPE

answer = CI = 3108 RUPEES

Step-by-step explanation:

i am doing the method in which u find the simple interest of first year then second year.

SI FOR 1ST YEAR= P X R X T / 100

SI = 2700 X 20 X 2 / 3 X 100 ( RATE OF INTEREST IS 20 / 3)

SI = 108000/300

SI = 360

SI FOR SECOND YEAR =

P = 2700 + 360= 3060

SI = 3060 X 20 X 2 / 300

SI= 122400 / 300

SI = 408

COMPOUND INTEREST (CI) = PRINCIPLE + SI OF 2ND YEAR

CI = 2700 + 408

CI = 3108 RUPEES

or u can solve be the method

CI = amount - principle

Amount= principle x (change in ratio) raised to time

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6 0

3 years ago

I need help finding the X in these equations

krek1111 [17]

Answer:

For D I believe it would be 6

Step-by-step explanation:

I believe 6 because is you do 108÷18 you get 6 and then it would be 6/108 = 7/18 which is true.

Might not be correct and I don't know the others sorry!

5 0

3 years ago

Consider and encode the following problem. The salt has been stolen! Well, it was found that the culprit was either the Caterpil

GenaCL600 [577]

The caterpillar ate the salt

3 0

3 years ago

Pleaseeeeeee help mee

BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

Step-by-step explanation:

Step(i):-

Given

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos( 3x - \frac{\pi }{3} ) = cos (\frac{\pi }{6} )$

$3x - \frac{\pi }{3} = \frac{\pi }{6}$

$3x - \frac{\pi }{3 } + \frac{\pi }{3} = \frac{\pi }{6} + \frac{\pi }{3}$

$3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}$

$x = \frac{\pi }{6}$

Step(ii):-

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

verification :-

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

put $x = \frac{\pi }{6}$

$cos( 3(\frac{\pi }{6}) - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} = \frac{\sqrt{3} }{2}$

Both are equal

∴The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

4 0

2 years ago

What is the distance from the origin to point A graphed on the complex plane below?

VMariaS [17]

On what point is A located? As in (x,y).

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3 years ago