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2 years ago

Write the equation of the line in slope-intercept form (y = mx + b) that has a slope of 4 and passes through the point (0,2).

Mathematics

1 answer:

Irina-Kira [14]2 years ago

4 0

Answer:

I need a graph.

Step-by-step explanation:

You can also use rise over run to help you. However if you are stating me that 4 is slope. Then it will be y=4x+ something because I am not sure if 2 is the y intercept even though its on the y-axis.

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Y=5x-4

anyanavicka [17]

Answer:

$\displaystyle -5x + y = -92\:or\:y = 5x - 92$

Step-by-step explanation:

−12 = 5[16] + b

$\displaystyle -92 = b \\ \\ y = 5x - 92$

If you want it in Standard Form:

y = 5x - 92

- 5x - 5x

__________

$\displaystyle -5x + y = -92$

I am joyous to assist you anytime.

7 0

3 years ago

Find The Area Of The Shape Shown Below

ruslelena [56]

Answer:42.55

Step-by-step explanation:

Les get the big boi out of the way first. We see that it is 3.5 by 9 and if we multiply we get 31.5. Next left triangle 2 by 2 so four but divided by 2 is 2. God so many 2's. So total is 33.5 so far. Next triangle is 2 by 5 soo 10 divided by 2 is 5. total is 38.5. Last dude in the middle. We know one side is two so we have to subtract here from the triangles which gets u the other side of 2 so 4. Total is 42.5

8 0

3 years ago

Read 2 more answers

The board of directors of a company knows that the probability that carbon emissions from the company’s factory exceed the permi

jekas [21]

the real answer is D. 0.9132

3 0

3 years ago

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Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

3 years ago

PLEASE HELP!! NO LINKS!! GIVING 20 POINTS AWAY!!

Kruka [31]

Answer:

m∠N = 32°

NQ = 106°

When finding inscribed angles like ∠N with the intercepted arc, the equation is ∠N=1/2MP. (Inscribed angles are always half the degree of the arc length.) Plug in the corresponding value to get ∠N=1/2(64) to get 32°. When finding the angle of the intercepted arc with inscribed angles like NQ, the equation is NQ=2(∠P). Plug in the corresponding value to get 2(53) to get 106°.

5 0

2 years ago

Read 2 more answers