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finlep [7]
3 years ago
8

1/4(-8x - 12) + -4 = 3/4(-8x - 12)

Mathematics
1 answer:
nekit [7.7K]3 years ago
8 0

Here's our equation:

\frac{1}{4} (-8x-12)-4=\frac{3}{4} (-8x-12)

Factor out the left side

(-2x - 3) - 4 = 3/4 (-8x - 12)

Simplify

-2x - 7 = 3/4 (-8x - 12)

Factor out the right side

-2x - 7 = -6x - 9

Add 7

-2x = 6x - 2

Add 6x to isolate the variable

4x = -2

Divide by 4

x = - 1/2

Here is how I simplified both sides initially. I'll only be showing the right side because this is a LOT of typing.

Begin with 3/4 (-8x - 12)

Use rule a*\frac{b}{c} = \frac{a * b}{c} to multiply

3(-8x-12)/4

Factor 3(-8x-12)

(-8x - 12) = (-4 * 2x - 4 * 3)

Simplify (-4 * 2x - 4 * 3)

-3 * 4 (2x+3)

- 12 (2x + 3)

Now that we've factored  3/4 (-8x - 12), we're left with- 12 (2x + 3)/4.

12/4 =3, giving us -3(2x + 3)

Distribute and simplify, then you're done.

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Answer:

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2) The year in which the amount of money in Laurie's account will become double is the year 2032

Step-by-step explanation:

1) The given information are;

The date Laurie made the investment = 1st, January, 2020

The annual interest rate of the investment = 5.5%

Type of interest rate = Compound interest

Therefore, we have;

The value, amount, of the investment after a given number of year, given as follows;

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The common ratio =  1.055

2) When the money doubles, we have;

2·a = a × rⁿ = a × 1.055ⁿ

2·a = a × 1.055ⁿ

2·a/a = 2 = 1.055ⁿ

2 = 1.055ⁿ

Taking log of both sides gives;

㏒2 = ㏒(1.055ⁿ) = n × ㏒(1.055)

㏒2 = n × ㏒(1.055)

n = ㏒2/(㏒(1.055)) ≈ 12.95

The number of years it will take for the amount of money in Laurie's account to double = n = 12.95 years

Therefore, the year in which the amount of money in Laurie's account will become double = 2020 + 12..95 = 2032.95 which is the year 2032

The year in which the amount of money in Laurie's account will become double = year 2032.

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