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3 years ago

1/4(-8x - 12) + -4 = 3/4(-8x - 12)

Mathematics

1 answer:

nekit [7.7K]3 years ago

8 0

Here's our equation:

$\frac{1}{4} (-8x-12)-4=\frac{3}{4} (-8x-12)$

Factor out the left side

(-2x - 3) - 4 = 3/4 (-8x - 12)

Simplify

-2x - 7 = 3/4 (-8x - 12)

Factor out the right side

-2x - 7 = -6x - 9

Add 7

-2x = 6x - 2

Add 6x to isolate the variable

4x = -2

Divide by 4

x = - 1/2

Here is how I simplified both sides initially. I'll only be showing the right side because this is a LOT of typing.

Begin with 3/4 (-8x - 12)

Use rule $a*\frac{b}{c} = \frac{a * b}{c}$ to multiply

3(-8x-12)/4

Factor 3(-8x-12)

(-8x - 12) = (-4 * 2x - 4 * 3)

Simplify (-4 * 2x - 4 * 3)

-3 * 4 (2x+3)

- 12 (2x + 3)

Now that we've factored 3/4 (-8x - 12), we're left with- 12 (2x + 3)/4.

12/4 =3, giving us -3(2x + 3)

Distribute and simplify, then you're done.

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Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

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