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Len [333]
2 years ago
6

2+3×=2×+3 ---> ×=1 Help please

Mathematics
1 answer:
vitfil [10]2 years ago
3 0

Answer It's gonna have to be i think mabey also 12

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Find an explicit formula for the arithmetic sequence below.<br> 9, 39/4, 21/2, 45/4, 12, 51/4,...
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F(n) = 9 + 0.75(n-1)
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What is the product in simplest form x^2+9x+18/x+2 times x^2-3x-10/x^2+2x-24
german
\dfrac{x^2+9x+18}{x+2}\cdot\dfrac{x^2-3x-10}{x^2+2x-24}=\dfrac{x^2+6x+3x+18}{x+2}\cdot\dfrac{x^2-5x+2x-10}{x^2+6x-4x-24}\\\\=\dfrac{x(x+6)+3(x+6)}{x+2}\cdot\dfrac{x(x-5)+2(x-5)}{x(x+6)-4(x+6)}

=\dfrac{(x+6)(x+3)}{x+2}\cdot\dfrac{(x-5)(x+2)}{(x+6)(x-4)}=\dfrac{(x+3)(x-5)}{x-4}\\\\=\dfrac{x^2-5x+3x-15}{x-4}=\dfrac{x^2-2x-15}{x-4}
5 0
3 years ago
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(a) What is the matrix representation of G, with vertices in numerical (ascending) order? (b) Consider using the Greedy Coloring
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Answer:

Check the explanation

Step-by-step explanation:

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The first term of a geometric sequence is 32, and the 5th term of the sequence is 818 .
sammy [17]

Answer:

32,24,18,\frac{27}{2} ,\frac{81}{8}

Step-by-step explanation:

Let x, y , and z be the numbers.

Then the geometric sequence is 32,x,y,z,\frac{81}{8}

Recall that  term of a geometric sequence  are generally in the form:

a,ar,ar^2,ar^3,ar^4

This implies that:

a=32 and ar^4=\frac{81}{8}

Substitute a=32 and solve for r.

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r^4=\frac{81}{256}

Take the fourth root to get:

r=\sqrt[4]{\frac{81}{256} }

r=\frac{3}{4}

Therefore x=32*\frac{3}{4} =24

y=24*\frac{3}{4} =18

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