N= -20/133
Step 1: Simplify both sides of the equation.
−
2
(
−
4
n
+
1
)
+
5
(
25
n
−
8
)
=
−
62
(
−
2
)
(
−
4
n
)
+
(
−
2
)
(
1
)
+
(
5
)
(
25
n
)
+
(
5
)
(
−
8
)
=
−
62
(Distribute)
8
n
+
−
2
+
125
n
+
−
40
=
−
62
(
8
n
+
125
n
)
+
(
−
2
+
−
40
)
=
−
62
(Combine Like Terms)
133
n
+
−
42
=
−
62
133
n
−
42
=
−
62
Step 2: Add 42 to both sides.
133
n
−
42
+
42
=
−
62
+
42
133
n
=
−
20
Step 3: Divide both sides by 133.
133
n
133
=
−
20
133
n
=
−
20
133
The equation we are looking at would have to be divided by 2 first.
x²-6x+3
When looking at that, I can tell that 1 may be the possible answer since you would have to subtract 6 from both sides. That would leave a 3. Let's check.
(x-3)(x-3)
x²-6x+9=6
Now subtract 6 from both sides.
x²-6x+3=0
So, 1- (x-3)²=6 would be used.
Answer:
lies between 0 and 1.
Step-by-step explanation:
We must have in mind that given average weight of a newborn panda is a non-integer rational number, such that lies between two integer rational number. In other words, this number must satisfy the following condition:
, 
Which is now developed mathematically to deduce a useful expression to find integers:
1) Given
2) 
Modulative property
3) 
Existence of Multiplicative inverse/Definition of division.
4) ![(n\cdot b)\cdot b^{-1} < a\cdot b^{-1}< [(n+1)\cdot b] \cdot b^{-1}](https://tex.z-dn.net/?f=%28n%5Ccdot%20b%29%5Ccdot%20b%5E%7B-1%7D%20%3C%20a%5Ccdot%20b%5E%7B-1%7D%3C%20%5B%28n%2B1%29%5Ccdot%20b%5D%20%5Ccdot%20b%5E%7B-1%7D)
Commutative, Associative and Distributive properties.
5) 
Compatibility with Multiplication/Existence of Multiplicative Inverse/Modulative Property/Result.
If we know that 
and 
, the following inequation is formed:
It is quite evident to conclude that lies between 0 and 1.
Answer:
answe is about 23. something
Step-by-step explanation:
