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dezoksy [38]
4 years ago
8

you bought a car for $24,500. you got a five-year loan for the car. You paid $9187.50 and simple interest. What was your interes

t rate?
Mathematics
1 answer:
Marysya12 [62]4 years ago
5 0
5.3 % interest rate...$$$
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The test scores of a geometry class are given below. 90, 75, 72, 88, 85 The teacher wants to find the variance for the class pop
ella [17]
The data given as a whole would be called ungrouped data. Now to get the variance, you will need the formula:

s^2=   <u>Σ(x-mean)^2</u>
                   n      

x = raw data
mean = average of all data
n = no. of observations
s^2 = variance

Now we do not have the mean yet, so you have to solve for it. All you need to do is add up all the data and divide it by the number of observations. 

Data: <span>90, 75, 72, 88, 85        n= 5  
</span>Mean=<u>Σx</u>
            n
Mean = <u>90+75+72+88+85 </u>  = <u>410</u> = 82
                        5                        5

The mean is 82. Now we can make a table using this.

The firs column will be your raw data or x, the second column will be your mean and the third will be the difference between the raw data and the mean and the fourth column will be the difference raised to two. 

90-82 = 8
8^2 =64

75-82 = -7
-7^2 =49

72-82 = -10
-10^2=100

88-82=6
6^2 = 12

85-82=3
3^2=9

Now you have your results, you can now tabulate the data:

 x      mean         x-mean        (x-mean)^2     
90       82                8                      64                       
75       82               -7                      49
72       82              -10                    100
88       82                6                       36
85       82                3                       9

Now that you have a table, you will need the sum of (x-mean)^2 because the sigma sign Σ in statistics, means "the sum of."

64+49+100+36+9 = 258

This will be the answer to your question. The value of the numerator of the calculation will be 258.

 
<u>
</u>
6 0
4 years ago
What is 120% of $590​
Nana76 [90]

Answer:

Tip

$708.00

Total

$1,298.00

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Give each rate in miles per hour:
DIA [1.3K]

a) 9/212 = #mph

b)0.000142045 Miles / 0.000277778 hours = # mph

Step-by-step explanation:

a) 9/212 = #mph

b)

1)9 inches divide the length value by 63360 is 0.000142045 Miles

2) 1 hour  3600 seconds in ones hour so 1/3600 =0.000277778

3) take miles/hour

0.000142045 Miles / 0.000277778 hours = # mph

6 0
3 years ago
What is 33 percent of 400
bearhunter [10]

Hi there :)


Answer: 33% of 400 is 132.


I found this answer because I multiplied 400 * 3 which equals 13,200.

then I divide 13,200 by 100 and then you will get your answer of 132.


I hope this helps you if you need any help, feel free to message me.


-Wolfs

7 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
4 years ago
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