What is the simplified form of the expression square root of -64
we have
![\sqrt[]{-64}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B-64%7D)
Remember that
64=2^6
and
i^2=-1
substitute
![\sqrt[]{-64}=\sqrt[]{(-1)(2^6)}=\sqrt[]{i^2\cdot2^6}=2^3i=8i](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B-64%7D%3D%5Csqrt%5B%5D%7B%28-1%29%282%5E6%29%7D%3D%5Csqrt%5B%5D%7Bi%5E2%5Ccdot2%5E6%7D%3D2%5E3i%3D8i)
<h2>option B</h2>
Answer:
(sin x)^2*(sec x) is positive in QII
Step-by-step explanation:
(sin x)^2 is always 0 or positive. Here x lies in QII.
sec x is positive when the adjacent side is positive and negative when the adjacent side is negative. In QII the adjacent side is positive.
In summary, (sin x)^2*(sec x) is positive in QII
Answer:
A: 30 m
B: 14 boxes
C: $596.40
D: $477.12
Step-by-step explanation:
A: 6*4.2 = 25.2. 3.2*1.5 = 4.8. 25.2 + 4.8 = 30.
B: 30/2.15 = 13.95, which rounds to 14.
C: 14*42.60 = $596.40
D: 20% off 100% = 80%, which is equal to 0.8. 596.40*.8 = $477.12.
Hope it helps you!! :)
