Hello,
4. you have sequences defined by the first term and a recursive relation.
Take n = 2, it gives
, right?
But you know 
so 
This is the second term. You are asked to find the first three terms.
Now, let's take n = 3
So the first three terms are 3, 6, 12.
6.
8.
10.
Do not hesitate if you have any question.
Thank you
Answer:
D. How many students enrolled in seventh grade at the start of this year
Answer:
a. The given equation is d = -75·t + 275 is a function
b. f(t) = -75·t + 275
c. 275 km
d. The situation does not makes sense for t > 11/2 hours.
Step-by-step explanation:
a. Given that a relation is a functional relation if for each input of a member in the relation, there is only one output for the other member, therefore;
The given equation is d = -75·t + 275 is a function
As when t = 1, d = 200 km
b. The equation written in functional notation, f(t) is f(t) = -75·t + 275
c. At the start of the journey, t = 0
Therefore;
f(0) = -75×0 + 275 = 275 km
d. The values of t that do no make sense in the function are given as follows
0 = -75×t + 275
t = 275/75 = 11/3 = 3.67 hours
For times above 3.67, the distance becomes negative
Therefore, the situation does not makes sense for t > 11/2 hours.
You can substitute it for 5.
2/5 = 0.4 = 40%
5/10 = 0.5 =50%
A) √50 = √(25 x 2) =√(5² x 2) = 5√2, what Jacklyn did is the other way round, instead of putting the perfect square out of the radical & keep the 2 inside, she inversed the sens of the operation
b) We have to find the square of the smaller & largest numbers that are near 50:
7² = 49 & 8² = 64==> so 49<50<64 & the number is between the square root of 7 & the square root of 8, but we also notice that 50 is very very near 49, hence let's try 7.1==> 7² = 7.1 x 7.1 = 50.41, which is a very good approximation. Then the approx. to √50 ≈ 50.41
