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mr_godi [17]
3 years ago
6

Solve the following equation. 4(x+2)-17=35

Mathematics
2 answers:
jasenka [17]3 years ago
6 0

Answer:

Step-by-step explanation:

x=11

guapka [62]3 years ago
6 0
The answer is 11
4(11+2)-17=35
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Two fair dice are rolled 3 times and the sum of the numbers that come up is recorded. Find the probability of these events. a. T
alexandr402 [8]

Answer:

Step-by-step explanation:

Given that two fair dice are rolled 3 times and the sum of the numbers that come up is recorded.

a) The sum is 4 on each of the three rolls.

(1,3) (2,2) (3,1) HEnce for one throw prob = 3/36 =1/12

Prob for getting same sum 4 in 3 rolls = (\frac{1}{12} )^3

(since each trial is independent)

b) Prob sum =4 in exactly 2 rolls

= 3C2 (1/12)^2 (11/12)=\frac{33}{12^3}

5 0
2 years ago
What does X equal??<br> Help quick
vagabundo [1.1K]
Correct Answer: x=17
7 0
3 years ago
5-star rating and brainiest
Lelu [443]

Answer:

Step-by-step explanation:

What to do??

8 0
3 years ago
Read 2 more answers
in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume
Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The m\angle CAB and m\angle CAD.

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

m(arcADC)=m(arcAD)+m(arcDC)

228^\circ=180^\circ+m(arcDC)

228^\circ-180^\circ+=m(arcDC)

48^\circ+=m(arcDC)

The measure inscribed angle is half of the corresponding subtended arc.

m\angle CAD=\dfrac{1}{2}\times m(arcDC)

m\angle CAD=\dfrac{1}{2}\times 48^\circ

m\angle CAD=24^\circ

AB is the tangent. So, m\angle BAD=90^\circ because radius is perpendicular on the tangent and the point of tangency.

m\angle BAD=m\angle CAB+m\angle CAD

90^\circ=m\angle CAB+24^\circ

90^\circ -24^\circ=m\angle CAB

66^\circ=m\angle CAB

Therefore, m\angle CAB=66^\circ and m\angle CAD=24^\circ.

4 0
2 years ago
Researchers have found that after 25 years of age the average size of the pupil in a
laila [671]

Answer:

At 25 = 6.8612mm

At 50 years = 5.422mm

Step-by-step explanation:

Equation,

d = 2.115Logₑa + 13.669

d = diameter of the pupil

a = number of years

Note : Logₑa = In a (check logarithmic rule)

d = 2.115Ina + 13.669

1. At 25 years,

d = -2.115In25 + 13.669

d = -2.115 × 3.2188 + 13.669

d = -6.807762 + 13.669

d = 6.8612mm

At 25 years, the pupil shrinks by 6.86mm

2. At 50 years,

d = -2.1158In50 + 13.669

d = -2.1158 * 3.912 + 13.669

d = -8.2770 + 13.699

d = 5.422mm

At 50 years, the pupil shirks by 5.422mm

To save this question, I had to plug in the values into the equation.

Solving for Logₑa might be difficult, so instead I used Inx which is the same thing. Afterwards, i substituted in the values and solve the equation for each years.

8 0
3 years ago
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