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Dima020 [189]
3 years ago
15

9squared plus 3 squared equals

Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0

Answer:

90

Step-by-step explanation:

9^2  +  3^2  equals:

81     +  9    = 90

nika2105 [10]3 years ago
3 0
90 is the answer. hope that helped
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In a statistics class there are 18 juniors and 10 seniors; 6 of the seniors are females and 12 of the juniors are males. If a st
Natasha_Volkova [10]

Answer:

P(a junior or a senior)=1

Step-by-step explanation:

The formula of the probability is given by:

P(A)=\frac{n(A)}{N}

Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.

In this case, N is the total number of the students of statistics class.

N=18+10=28

The probability of the union of two mutually exclusive events is given by:

P(AUB)=P(A)+P(B)

Therefore:

P(a junior or a senior) =P(a junior)+P(a senior)

Because a student is a junior or a senior, not both.

n(a junior)=18

n(a senior)=10

P(a junior)=18/28

P(a senior) = 10/28

P(a junior or a senior) = 18/28 + 10/28

Solving the sum of the fractions:

P(a junior or a senior) = 28/28 = 1

4 0
3 years ago
What is the reason for Statement 5 of the two-column proof?
zmey [24]

Given: ∠JNL and ∠MNK are vertical angles and  m∠MNK=90°

Prove: ∠JNL is a right angle.

   Statements                                                     Reasons

1.  ∠JNL and ∠MNK are vertical angles.             Given

2. \angle JNL \cong \angle MNK        Vertical angle theorem

3. m \angle JNL = m \angle MNK        Angle congruence postulate

4.  m \angle MNK = 90^\circ                Given

5. m \angle JNL = 90^\circ                 <u> Substitution Property of Equality</u>

Since, the measures of angle JNL and MNK are equal and the measure of angle MNK is 90 degrees. therefore, by substitution property of equality, both the angles JNL and MNK will have an equal measure.

Therefore,  m \angle JNL = 90^\circ

6. ∠JNL is a right angle.                                     Definition of right angle

8 0
3 years ago
Read 2 more answers
Deirdre plotted a point D in Quadrant IV. After she reflected the point across an axis, the reflection was in Quadrant III. Give
Lostsunrise [7]
It depend on what d was. anything in Q3 can work for the reflection and both x and y are negative, you can say that for sure. for the actual point D, anything in Q4. in Q4 x is positive and y is negative. if d is (3,-3) then it's reflection is (-3,-3)
8 0
3 years ago
A homeowner's electric bill for the month was $155.80 for 1,900 kilowatt-hours of
sergij07 [2.7K]
I’m almost done solving this
3 0
3 years ago
Verify the identity. (cos x/ 1+ sin x) + (1+ sin x/cos x) = 2 sec x​
Gekata [30.6K]

Answer:

LHS

\frac{cos x}{1+ sin x} + \frac{1+ sin x}{cos x} \\=\frac{cos2(x)+1+2sin(x)+sin2(x)}{cos(x)(1+sin(x)} \\= \frac{2+2sin(x)}{cos(x)(1+sin(x))} \\\\=\frac{2 (1 + sin(x))}{cos(x)(1+sin(x))} \\= \frac{2}{cos (x)} \\= 2 sec x

= RHS PROVED

hope it helps :)

8 0
3 years ago
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