.Answer:
Step-by-step explanation:
Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
Answer:
2x, (x-2), (x+6)
Step-by-step explanation:
I just took the quiz on plato and I got it correct
P.S Can you guys give me the brainliest please
Answer:
Round 1.9 to 2 cm and multiply by 18.
Step-by-step explanation:
Round 1.9 to 2 cm and multiply by 18. then you will get your answer
Answer:
true?
Step-by-step explanation:
im guessing.
