7-14m=2m=5 please help

H=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
<span>(the whole left side of the equation is divided by 2 i just cant do it on the computer)</span>

7 0

3 years ago

rob is asked to graph this system of equations: 6x + 2y = 5; y + 3x =2; how many times will the lines intersect? A. there is no

9966 [12]

Answer:

C

Step-by-step explanation:

A and B are wrong and with D they wouldn't be lines so imma go with C.

Sorry if it's wrong.

6 0

3 years ago

Amy joined a DVD rental club. She paid an initial fee of $15.87 and it costs $0.82 per DVD she rents. The expression to show the

MrMuchimi

Answer:

$45.34

hope this helps

6 0

3 years ago

Read 2 more answers

Find the extreme values of f(x y)=xy subject to the constraint x^2 + y^2 -4 = 0

KATRIN_1 [288]

Via Lagrange multipliers:

$L(x,y,\lambda)=xy+\lambda(x^2+y^2-4)$

$L_x=y+2\lambda x=0$
$L_y=x+2\lambda y=0$
$L_\lambda=x^2+y^2-4=0$

$yL_x=y^2+2\lambda xy=0$
$xL_y=x^2+2\lambda xy=0$
$\implies yL_x-xL_y=y^2-x^2=0\implies y^2=x^2$
$\implies x^2+y^2=4=2x^2\implies x^2=2\implies x=\pm\sqrt2\implies y=\pm\sqrt2$

So we have four critical points to consider, $(\sqrt2,\sqrt2),(-\sqrt2,\sqrt2),(\sqrt2,-\sqrt2),(-\sqrt2,-\sqrt2)$ . If both coordinates are positive or both are negative, we get a maximum value of $(\pm\sqrt2)^2=2$ ; otherwise, we get a minimum of $(-\sqrt2)(\sqrt2)=-2$ .

4 0

3 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

2.

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0

3 years ago

7-14m=2m=5 please help​

7-14m=2m=5 please help