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Kisachek [45]
3 years ago
5

How many cubic feet of water can the following in ground swimming pool hold

Mathematics
2 answers:
denis-greek [22]3 years ago
7 0
Jshdhdijs?? 474883 Shan’s 56
pashok25 [27]3 years ago
3 0
What pool? Any of these answers work when we don’t know what pool...
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Divide 6 by 2/3
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Which statement is true about -14 and -8?
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A

Step-by-step explanation:

-14>-8 because -14 is located to the left of -8 on the number line.

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Find the area of the figure.
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16 is the answer add all side door

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There are 135 people in a sport centre. 73 people use the gym. 59 people use the swimming pool. 31 people use the track. 19 peop
wlad13 [49]

Answer:

Probability that the person doesn't use any facility = 0.0889

Step-by-step explanation:

Total number of people in a sports center = 135

Number of people using gym 'G' = 73

Number of people using swimming pool 'P' = 59

Number of people using track 'T' = 31

Number of people using gym and pool (G∩P) = 19

Number of people using pool and track (P∩T) = 9

Number of people using gym and track (G∩T) = 16

Number of people using all three facilities (G∩P∩T) = 4

Therefore, from the rule of compound probability,

P(GUPUT) = P(G) + P(P) + P(T) - P(G∩P) - P(G∩T) - P(P∩T) + p(G∩P∩T)

We know probability of an event = \frac{\text{Favorable event}}{\text{Total outcomes}}

We will plug in the values of probabilities of each event in the formula.

P(GUPUT) = \frac{73}{135}+\frac{59}{135}+\frac{31}{135}-\frac{19}{135}-\frac{9}{135}-\frac{16}{135}+\frac{4}{135}

                 = \frac{1}{135}(73+59+31-19-9-16+4)

                 = \frac{123}{135}

And probability that a person doesn't use any facility = 1 - P(GUPUT)

= 1 - \frac{123}{135}

= \frac{135-123}{135}

= \frac{12}{135}

= \frac{4}{45} ≈ 0.0889

7 0
4 years ago
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10. The sum of the digits of a three-digit number is 11. If the digits are reversed, the new number is 46
Zarrin [17]

Answer:

hope this helps

Step-by-step explanation:

The sum of the digits of a three-digit number is 11.

If the digits are reversed, the new number is 46 more than five times the old number.

If the hundreds digit plus twice the tens digit is equal to the units digit, then what is the number?

:

Write an equation for each statement:

:

"The sum of the digits of a three-digit number is 11."

x + y + z = 11

:

The three digit number = 100x + 10y + z

The reversed number = 100z + 10y + x

:

" If the digits are reversed, the new number is 46 more than five times the old number."

100z + 10y + x = 5(100x + 10y + z) + 46

100z + 10y + x = 500x + 50y + 5z + 46

combine on the right

0 = 500x - x + 50y - 10y + 5z - 100z + 46

499x + 40y - 95z = -46

:

"the hundreds digit plus twice the tens digit is equal to the units digit,"

x + 2y = z

x + 2y - z = 0

:

Three equations, 3 unknowns

:

x + y + z = 11

x +2y - z = 0

-----------------Addition eliminates z

2x + 3y = 11

From the 2nd equation statement, we know that the 1st original digit has to be 1

2(1) + 3y = 11

3y = 11 - 2

3y = 9

y = 3 is the 2nd digit

then

1 + 3 + z = 11

z = 11 - 4

z = 7

:

137 is the original number

:

:

Check solution in the 2nd statement

If the digits are reversed, the new number is 46 more than five times the old number."

731 = 5(137) + 46

731 = 685 + 46

7 0
3 years ago
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