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Kisachek [45]
3 years ago
5

How many cubic feet of water can the following in ground swimming pool hold

Mathematics
2 answers:
denis-greek [22]3 years ago
7 0
Jshdhdijs?? 474883 Shan’s 56
pashok25 [27]3 years ago
3 0
What pool? Any of these answers work when we don’t know what pool...
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1. Find the domain and range of the function<br> f(x)=√1-4x².
slamgirl [31]

f(x) =  \sqrt{1 - 4{ x}^{2} }

1 - 4x {}^{2}  \geqslant 0

-  \infty  \:  \:  \:  \:  \:  \:  \:  \:  - 0.5 \:  \:  \:  \:  \:  \:  \:  \:  \: 0.5 \:  \:  \:  \:  \:  \:  \: \:   \infty  \\   -  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \: \:0  \:  \: \:  \:  \:   +  \:  \:  \:  \:0 \:  \:  \:  \:  \:   -

domain \\ [ \: -0.5 \: , \: 0.5 \: ]

g(x) = 1 - 4x {}^{2}  \\ g'(x) =  - 8x \\ g'(x) = 0 \\ x = 0 \\ g(0) = 1 - 4(0) = 1 \\ maximum \:  = 1

range  \\ [ \: 0 \:  ,  \: 1 \: ]

5 0
2 years ago
Read 2 more answers
The coordinate m is 2.5 and mn=4. What are the possible coordinates for n
steposvetlana [31]
Refer to the figure shown below.

The coordinates of point m are (2,5).
Let (x,y) = the coordinates of pont n.

Because mn = 4, use the Pythagorean theorem to obtain
(x - 2)² + (y - 5)² = 4²

This represents a circle with center at (2,5) and radus = 4.

Answer:
Possible coordinates for n lie on the circle (x-2)² + (y-5)² = 16.

7 0
3 years ago
Write a System of Linear Inequalities
Neko [114]
Answer:

1.50x+2.50y=25
x+y=6

hope this helps!
4 0
3 years ago
Basic Computation: Find Probabilities In Problems 5-14, assume that x has a normal distribution with the specified mean and stan
Ulleksa [173]

Answer:

the answer is below

Step-by-step explanation:

The z score is used to calculate by how many standard deviations the raw score is above or below the mean. The z score is given as:

z=\frac{x-\mu}{\sigma}\\\\\mu=mean,\sigma=standard\ deviation

1) For x = 3

z=\frac{x-\mu}{\sigma}=\frac{3-4}{2}=-0.5

For x = 6

z=\frac{x-\mu}{\sigma}=\frac{6-4}{2}=1

P(3 ≤ x ≤ 6) = P(-0.5 ≤ z ≤ 1) = P(z < 1) - P(z < -0.5) = 0.8413 - 0.3085 = 0.5328

2) For x = 50

z=\frac{x-\mu}{\sigma}=\frac{50-40}{15}=0.67

For x = 70

z=\frac{x-\mu}{\sigma}=\frac{70-40}{15}=2

P(50 ≤ x ≤ 70) = P(0.67 ≤ z ≤ 2) = P(z < 2) - P(z < 0.67) = 0.9772 - 0.7486 = 0.2286

3) For x = 8

z=\frac{x-\mu}{\sigma}=\frac{8-15}{3.2}=-2.19

For x = 12

z=\frac{x-\mu}{\sigma}=\frac{12-15}{3.2}=-0.94

P(8 ≤ x ≤ 12) = P(-2.19 ≤ z ≤ -0.94) = P(z < -0.94) - P(z < -2.19) = 0.1736 - 0.0143 = 0.1593

4) For x = 30

z=\frac{x-\mu}{\sigma}=\frac{30-20}{3.4}=2.94

P(x ≥ 30) = P(z ≥ 2.94) = 1 - P(z < 2.94) = 1 - 0.9984 = 0.0016

5)  x = 90

z=\frac{x-\mu}{\sigma}=\frac{90-100}{15}=-0.67

P(x ≥ 90) = P(z ≥ -0.67) = 1 - P(z < -0.67) = 1 - 0.2514 = 0.7486

6)  For x = 10

z=\frac{x-\mu}{\sigma}=\frac{10-15}{4}=-1.25

For x = 20

z=\frac{x-\mu}{\sigma}=\frac{20-15}{4}=1.25

P(10 ≤ x ≤ 20) = P(-1.25 ≤ z ≤ 1.25) = P(z < 1.25) - P(z < -1.25) = 0.8944 - 0.1056 = 0.7888

7)  For x = 7

z=\frac{x-\mu}{\sigma}=\frac{7-5}{1.2}=1.67

For x = 9

z=\frac{x-\mu}{\sigma}=\frac{9-5}{1.2}=3.33

P(7 ≤ x ≤ 9) = P(1.67 ≤ z ≤ 3.33) = P(z < 3.33) - P(z < 1.67) = 0.9996 - 0.9525 = 0.0471

8)  For x = 40

z=\frac{x-\mu}{\sigma}=\frac{40-50}{15}=-0.67

For x = 47

z=\frac{x-\mu}{\sigma}=\frac{47-50}{15}=-0.2

P(40 ≤ x ≤ 47) = P(-0.67 ≤ z ≤ -0.2) = P(z < -0.2) - P(z < -0.67) = 0.4207 - 0.2514 = 0.1693

9)  x = 120

z=\frac{x-\mu}{\sigma}=\frac{120-10}{15}=7.33

P(x ≥ 120) = P(z ≥ 7.33) = 1 - P(z < 7.33) = 1 - 0.9999 = 0.001

10) x = 2

z=\frac{x-\mu}{\sigma}=\frac{2-3}{0.25}=-4

P(x ≥ 2) = P(z ≥ -4) = 1 - P(z < -4) = 1 - 0.0001 = 0.999

3 0
3 years ago
Can someone please help me out
amm1812

I believe it’s b

It is the one in between and closest to the amount that you need

8 0
3 years ago
Read 2 more answers
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