Ok, first put in the -2 for each b. That gives:
|-4(-2)-8|+|-1(-(-2))^2|+2(-2)^3
Let's do each section.
The first section is |-4(-2)-8)|
-4 times -2 is 8, minus 8 is 0. The absolute value of 0 is still 0.
Now we move on to |-1(-(-2))^2)|
First we do exponents
-(-2) is 2, and 2^2 is 4. 4 times -1 is -4. The absolute value of -4 is 4
Now the last section, 2(-2)^3
Exponents first: (-2)^3 is -2 * -2 * -2, which is -8.
-8*2=-16.
0+4+(-16)=-12
Let, the length = l
Width = l/2
Area = l * w = l * l/2 = l²/2
So, Your Final Answer would be A = l²/2
Hope this helps!
Answer:
(2x+3y)(2x-3y)
Step-by-step explanation:
a² - b² = (a + b)(a - b)
4x² - 9y²
= (2x)² - (3y)²
= (2x + 3y)(2x - 3y)
Answer: See the figure attached.
Step-by-step explanation:
Observe the figure attached. The vertices of the triangle ABC have the following coordinates:
A(2,5); B(6,2) and C(3,-5)
To graph the image (in this case we can identify it as A'B'C'), you must use the rule
→
.
Then, you have to subtract 6 units from the x-coordinate of each vertex and subtract 4 units from the y-coordinate of each vertex.
Therefore, you get:
Vertex A'→ 
Vertex B'→ 
Vertex C'→ 
Having the vertices of the image A'B'C', you can graph it (See the figure attached).