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3 years ago

What is 1704 divided by 18

Mathematics

1 answer:

Oksana_A [137]3 years ago

6 0

Answer:

94.6666666667

Step-by-step explanation:

use a calculator...or you can just divide both those numbers by two and simplify the question

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Hey ma i need your help on this plz and ill give you a branist or wtv its called

Luden [163]

Hi there!

$\large\boxed{\text{ sum = 180(n - 2)}}$

This is the formula for finding the sum of interior angles for a polygon with a number of sides "n".

We can also prove this from the table:

Triangle ⇒ 3 sides: 180(3 - 2) = 180°

Quadrilateral ⇒ 4 sides: 180(4 - 2) = 360°

Pentagon ⇒ 5 sides: 180(5 - 2) = 540°

...And so forth. We can write this as for any polygon with "n" sides:

180(n - 2) = sum (°)

3 0

3 years ago

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Lupe had a difficult time during her last group discussion. She knew her topic, but she got confused as others were talking, esp

11Alexandr11 [23.1K]

Answer: yes they should do all of those

Step-by-step explanation:

Try to elaborate more also

4 0

3 years ago

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What is the area of a triangle ABC with AB=AC=5cm and BC=6cm?

Vika [28.1K]

Answer: 12 cm^2

Step-by-step explanation:

BC ==> Base of triangle

Divide the triangle in two parts:

BC/2=BC'

6/2=BC'

BC'=3

Distance formula: a^2+b^2=c^2

c^2-a^2=b^2

5^2-3^2=b^2

25-9=b^2

b^2=16

b=4 ==> height of triangle

Area of triangle=A. b=base. h=height

A=1/2 * b * h=

A=1/2 * 6 * 4

A=1/2 * 24

A=12 cm^2

8 0

1 year ago

1. In which quadrant does θ lie given that sinθ>0 and cosθ<0?

expeople1 [14]

Answer:

$\theta$ is in quadrant II

Step-by-step explanation:

Given

$\sin(\theta) > 0$ and $\cos(\theta) < 0$

Required

Where is $\theta$

$\sin(\theta) > 0$ and $\cos(\theta) < 0$ imply that

$\theta$ is in quadrant II

Because that is only quadrant where $\sin(\theta) > 0$ and $\cos(\theta) < 0$ exist.

4 0

3 years ago

Hich of the following is an even function? f(x) = (x – 1)2 f(x) = 8x f(x) = x2 – x f(x) = 7

Ede4ka [16]

<u>Answer:</u>

f(x) = 7 is an even function.

<u>Step-by-step explanation:</u>

Any function is even when $f(x) = f(-x)$ and gives a graph that is symmetric with respect to the y-axis.

We are given these options and we have to check whether which of them is an even function:

$f(x)= (x-1)^2$ $= x^2-2x+1$

and $f(-x) = (-x - 1)^2 = x^2 + 2x + 1$ - This function is not even

$f(x) = 8x$

and $f(-x) = -8x$ - This function is not even

$f(x)=x^2-x$

and $f(-x) = (-x)^2 + x = x² + x$ - This function is not even

$f(x) = 7$

and $f(-x) = 7$ - EVEN FUNCTION

We get the same value for $f(x)$ and $f(-x)$ , therefore f(x) = 7 is an even function.

8 0

3 years ago

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