These types of pieces forces us to think about them, however, it does not matter how it’s the most important, what matters is how it makes you, yourself feel, this kind of abstract art is strictly real and gives us space to think on our own, patterns and unity in work , homogeneity and uniqueness are the most factors that defines the good paint or failure on.

5 0

3 years ago

Factor-

Nastasia [14]

Hello from MrBillDoesMath!

Answer:

See Discussion section below

Discussion:

2x^2 + 5x + 3 = (2x+3)(x+1) which is Choice 3

3x^2+10x+4 =-1/3 (-3 x + sqrt(13) - 5) (3 x + sqrt(13) + 5)

I don't think any of the provided choices are right!

8x^2+10x-3 = (2x+3)(4x-1) which is Choice 2

6x^2-7x-4 = -1/24 (-12 x + sqrt(145) + 7) (12 x + sqrt(145) - 7)

I don't think any of the provided choices are right!

2x^2+x-28 = (2x-7)(x+4) which is Choice 2

Thank you,

MrB

4 0

3 years ago

If there are 17 green marbles in a jar of 65 marbles, what is the probability of drawing 2 green marbles at random without repla

erastovalidia [21]

Answer:

Option b) $\frac{17}{260}$

Step-by-step explanation:

We are given the following information in the question:

Total number of marbles = 65

Number of green marbles = 17

We have to find the probability of drawing 2 green marbles at random without replacement.

Formula:

$Probability = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

$\text{P(Drawing 2 green marbles at random without replacement)} = \\\text{Probability of drawing }1^{st} \text{ green marble}\times \text{Probability of drawing }2^{nd} \text{ green marble}$

$\text{Probability of drawing }1^{st} \text{ green marble} = \displaystyle\frac{17}{65}\\\\\text{Probability of drawing }2^{nd} \text{ green marble} = \displaystyle\frac{16}{64}$

$\text{P(Drawing 2 green marbles at random without replacement)} =\displaystyle\frac{17}{65}\times \frac{16}{64}=\frac{17}{260}$

Option b) $\frac{17}{260}$

5 0

3 years ago