Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
Answer:
65
Step-by-step explanation:
First, order the numbers in order. Then find the "middle numbers" and omit them after you have divided the number set into two equals parts. Then find the median of those number sets and then subtract.
You should get 71-6 at the end which is 65.
X, y - the numbers
The numbers multiply to 100.
The numbers add up to -29.
Substitute -x-29 for y in the first equation:
The numbers are
-4 and
-25.
Answer:
I think it's true. hope this helps!!
Answer:
n=15
Step-by-step explanation:
subtract 8 from both sides to get 3n=45
divide both sides by 3 to solve for n to get n=15
