Answer:
D) 1/36
Step-by-step explanation:
You are trying to roll a 3 the first time, and then a 5 the second time. This means that order matters.
It is given to you, that you are rolling a standard die (6-sides). The dice is ordered in the following: 1, 2, 3, 4, 5, 6
The first time, you are rolling for a 3. Note that there is only one 3 in the sequence, so your chance of rolling a 3 is 1 out of 6: 1/6.
The second time, you are rolling for a 5. Note that there is only one 5 in the sequence, so your chance of rolling a 5 is 1 out of 6: 1/6.
Next, multiply the two fractions together to find the probability of rolling a 3 and then a 5:
1/6 x 1/6 = (1 x 1)/(6 x 6) = 1/36
D) 1/36 is your answer.
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Answer:
What type of angle is it?
Step-by-step explanation:
Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
The formula is (2)(n-4) = n-1/4
Mult both sides by 4:
8n - 32 = 4n -1, or 4n = 31, or n=31/4.
If this is not what you expected, please ensure that you have copied down the original problem correctly. What do you mean by "1/4 less?"
Let's try (2)(n-4) = 1n-(1/4)n = (3/4)n. Then,
2n-8 = (3/4)n, or (5/4)n = 8. Mult. both sides by (4/5), we get:
n = (5/4)(8) = 10. Is that what you were hoping for?
