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serious [3.7K]
3 years ago
15

Order the fractions from least to greatest.1. 3/10 3/6 2/52. 3/8 1/3 3/12​

Mathematics
1 answer:
shusha [124]3 years ago
6 0

Answer:

1. 3/10, 2/5, 3/6 2. 3/12, 1/3, 3/8

i hope this helps!

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FG ∥ CB, A ∈ FG, D ∈ AB, E ∈ AC
andrey2020 [161]

Answer:

The value of x is 31^{\circ}.

Step-by-step explanation:

Please look at the figure attached to get more clear solution.

We have given:

FG||CB

And the line that cut the parallel line is transversal so, here BA is transversal

And alternate interior angles on transverse line are equal

So, ∠1=∠4

And ∠4=28^{\circ}

Hence,  ∠1=∠4=28^{\circ}

And On FG the sum of angles will be 180^{\circ}

∠3+∠2+∠1=180^{\circ}

90^{\circ}+∠2+28^{\circ}=180^{\circ}

Hence, ∠2=62^{\circ}

Now, we know that the sum of interior angles is equal to the exterior angle:

Therefore, ∠2+∠5=∠6+∠7

62^{\circ}+3x=x+4x

On simplification we get:

2x=62^{\circ}

x=31^{\circ}

Hence, the value of x is 31^{\circ}.

3 0
3 years ago
What is the probability of selecting a red jack from a deck of cards?
Ostrovityanka [42]

Answer:

There's 2 red jacks in a deck and 2 black queens in a deck so you have a total of 4 possible cards out of a 52 total in a deck so that would be 4/52 or 1/13 of the time. Statistically 7.6% of the time you will get a red jack or a black queen.

Step-by-step explanation:

3 0
2 years ago
Maddi has a bin shaped like a right prism. She knows that the area of the base of the bin is 14 in² and the volume of the bin is
Oksana_A [137]

Answer:

The answer is 28 in

Step-by-step explanation:

I divided 392/14=28

hopefully it helps.

please mark brainliest.

8 0
2 years ago
Read 2 more answers
Can someone please help me asap?
pashok25 [27]

find the area the get the premiraterStep-by-step explanation:add

3 0
2 years ago
Helpppppppppppppppppp!
julia-pushkina [17]
Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.

If the domain has already been restricted to x \geq -11, we can work backwards to add 11 to both sides. We see that x+11 must be under the radicand, so the answer is A.
7 0
3 years ago
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