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Ivenika [448]
3 years ago
10

He truck is rented at $40 per day plus they charge per mile of use the truck travel 15 miles in one day and the total charge was

115 which equation can be used to find the X charge in dollars per mile traveled?
Mathematics
2 answers:
strojnjashka [21]3 years ago
8 0
15x + 40 = 115

We set the equation to 115 because the total cost is $115.
We add the "+ 40" because of the $40 to rent the trailer for the day.
The 15x is because it represents the miles per hour (x) times the number of hours.

The number of hours times the charge per mile, plus the $40 to rent it, will equal $115.

Hope this helps!!
Allushta [10]3 years ago
7 0

Answer:

115 = 15 x + 40

the charge is $5 dollars per mile

Step-by-step explanation:

He truck is rented at $40 per day plus they charge per mile of use the truck travel 15 miles in one day and the total charge was 115

LEt x  be  the charge in dollars per hour

Initial charge is 40 and 15 miles travelled  in one day

total charge = 15x + 40

Given : total charge is 115

So the equation becomes

115 = 15 x + 40

Now we solve for x

Subtract 40 from both sides

75= 15 x

Divide both sides by 15

x= 5

so , the charge is $5 dollars per mile

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A manufacturer must test that his bolts are 4.00 cm long when they come off the assembly line. He must recalibrate his machines
storchak [24]

Answer:

The null hypothesis is H_o: \mu = 4.

The alternate hypothesis is H_a: \mu \neq 4

The pvalue of the test is 0.0182 < 0.05, which means that there is sufficient evidence to show that the manufacturer needs to recalibrate the machines.

Step-by-step explanation:

A manufacturer must test that his bolts are 4.00 cm long when they come off the assembly line.

This means that the null hypothesis is that they are 4.00 cm long, that is:

H_o: \mu = 4

At the alternate hypothesis we test if it is different. So

H_a: \mu \neq 4

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

4 is tested at the null hypothesis:

This means that \mu = 4

After sampling 196 randomly selected bolts off the assembly line, he calculates the sample mean to be 4.14 cm.

This means that n = 196, X = 4.14

He knows that the population standard deviation is 0.83 cm.

This means that \sigma = 0.83

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z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{4.14 - 4}{\frac{0.83}{\sqrt{196}}}

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Pvalue of the test and decision:

The pvalue of the test is the probability that the sample mean is different by at least 4.14 - 4 = 0.14 from the target value, which is P(|z| > 2.36), which is 2 multiplied by the pvalue of z = -2.36.

Looking at the z-table, z = -2.36 has a pvalue of 0.0091

2*0.0091 = 0.0182

The pvalue of the test is 0.0182 < 0.05, which means that there is sufficient evidence to show that the manufacturer needs to recalibrate the machines.

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2 years ago
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