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3 years ago

write an equation for the line that passes through the point (8,3) and parallel to -4x+8y=23. Use slope-intercept form.

1 answer:

6 0

(1/2)x+b=y because the equation that given the slope is 1/2 if you leave y alone and take the x’s number

put the point now , 4+b=3 so b is -1

the equation is (1/2)x-1=y

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Which graph shows the solution to the equation below log3(x+3)=log0.3(x-1)

algol13

Answer: did you get the answer??????

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

-4/4- (-8/4) Write answer as a decimal

olga_2 [115]

-4/4 can be reduced to -2.
(-8/4) can be reduced to -1.
What you have to do next is to add -1-(-2).
The final answer is 1.
Hope that helps!!!.

8 0

3 years ago

Can someone help me please please?

erastovalidia [21]

Answer:

Step-by-step explanation:

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2 years ago

Use the law of sines to find what Angle R is:

stich3 [128]

Answer:

Step-by-step explanation:

So, according to the law of Sines, we have

$\frac{Sin(A)}{a} = \frac{Sin(b)}{b}$

In our case, we have S and R, so...

$\frac{Sin(S)}{s} = \frac{Sin(R)}{r}$

And we want to isolate R...

$r = sin^{-1} (\frac{Sin(S) * r}{s} ) = sin^{-1} (\frac{Sin(52) * 32}{26} ) = 75.90$

the angle of R is then 75.90 degrees.

5 0

3 years ago

An electronics company produces transistors, resistors, and computer chips. Each transistor requires 3 units of copper, 1 unit

padilas [110]

Answer:

An electronics company can be produce 350 transistors and 340 computer chips, they can´t produce resistors.

Step-by-step explanation:

1. We will name the variables for transistors, resistors and the computer chips.

a = Transistors

b= Resistors

c = Computer chips

2. We propose three linear equations, one for the copper, one for the zinc and one for the glass.

$\left \{ {{3a+3b+2c=1730} \atop {a+2b+c=690}}\atop {2a+b+2c=1380}} \right.$

3. We write the matrix form as Ax=d

$A=\left(\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right)$

$x=\left(\begin{array}{ccc}a\\b\\c\end{array}\right)$

$A=\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)$

With this formula the solution of x is $x=\frac{d}{A}$ or $x=A^{-1}d$

4. We will find the inverse matrix $A^{-1}$ using the formula:

$A^{-1} = \frac{1}{detA} (C_{A})^{T}$

a. det A

$det A=\left[\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right] =3*(4-1)-3*(2-2)+2*(1-4)=9-0-6=3$

b. $(C_{A})^{T}$

$C_{A}=\left(\begin{array}{ccc}4-1&.(2-2)&1-4\\-(6-2)&6-4&-(3-6)\\3-4&-(3-2)&6-3\end{array}\right)$

$C_{A}=\left(\begin{array}{ccc}3&.0&-3\\-4&2&3\\-1&-1&3\end{array}\right)$

$(C_{A}) ^T=\left(\begin{array}{ccc}3&0&-3\\-4&2&3\\-1&-1&3\end{array}\right)^T$

$(C_{A}) ^T=\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)$

c. $A^{-1}$

$A^{-1}=\frac{1}{3} \left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)$

5. As $x=\frac{d}{A}$ or $x=A^{-1}d$ , the solution of x is:

$x=\frac{1}{3}\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)$

$x=\frac{1}{3}\left(\begin{array}{ccc}(3*1730)+(-4*690)+(-1*1380)\\(0*1730)+(2*690)+(-1*1380)\\(-3*1730)+(3*690)+(3*1380)\end{array}\right)$

$x=\frac{1}{3}\left(\begin{array}{ccc}1050\\0\\1020)\end{array}\right)$

$X=\left[\begin{array}{ccc}350\\0\\340\end{array}\right]$

Therefore:

a= 350 Transistors

b=0 Resistors

c=340 Computer chips

4 0

2 years ago