Question

What is the probability of getting a sum of 6 when rolling two number cubes? 1/12 1/9 1/6 5/36

Answer 1

prob ( 2 then a 4) = 1/6 * 1/6 = 1/36

prob( 4 then a 2) = 1/36

Prob ( two 3's) = 1/36

Prob (1 and 5 or 5 and 1) = 1/18

So it is 3/36 + 1/18 = 3/36 + 2 /36 = 5/36 Answer

Answer is

Answer 2

$|\Omega|=6^2=36\\ |A|=5\\\\ P(A)=\dfrac{5}{36}$