Ask question

Ask question

All categories

3 years ago

11

What is the probability of getting a sum of 6 when rolling two number cubes? 1/12 1/9 1/6 5/36

2 answers:

zysi [14]3 years ago

5 0

prob ( 2 then a 4) = 1/6 * 1/6 = 1/36

prob( 4 then a 2) = 1/36

Prob ( two 3's) = 1/36

Prob (1 and 5 or 5 and 1) = 1/18

So it is 3/36 + 1/18 = 3/36 + 2 /36 = 5/36 Answer

Answer is

Ivenika [448]3 years ago

3 0

$|\Omega|=6^2=36\\ |A|=5\\\\ P(A)=\dfrac{5}{36}$

You might be interested in

A dog is leashed to the corner of a house with a 20 ft long leash. How much running area does the dog have? Round your answer to

11111nata11111 [884]

Answer:

The dog's running area is approximately 942 feet².

Step-by-step explanation:

The dog is leashed to a fixed point, the leash has a length of 20 ft, therefore he can rotate around that point at the maximum distance equal to the length of the leash. This pattern forms a circle, but there is an obstruction, which is the corner of the house. This obstruction takes an arc of the original circle, so the running area of the dog is the area of the whole circle minus the area of the arc formed by the corner of the house.

$\text{dog's area} = \text{circle's area} - \text{arc's area}\\\\\text{dog's area} = pi*(20^2) - \frac{90}{360}*pi*(20^2)\\\\\text{dog's area} = \frac{270}{360}*pi*(400)\\\\\text{dog's area} = 942.477\text{ feet}^2$

The dog's running area is approximately 942 feet².

3 0

3 years ago

A skier is trying to decide whether or not to buy a season ski pass. A daily pass costs $69. A season ski pass costs $350. The

zalisa [80]

Divide the season pass cost by the daily capstone:

350 / 69 = 5.07

They would have to ski 6 days for the season pass to be less expensive

7 0

3 years ago

Plzzzz help me on this questions fast <br><br>This is Trigonometry

Sladkaya [172]

Answer:

x ≈ 20.42, y ≈ 11.71

Step-by-step explanation:

Using the cosine ratio on the right triangle on the right, that is

cos20° = $\frac{adjacent}{hypotenuse}$ = $\frac{11}{y}$

Multiply both sides by y

y × cos20° = 11 ( divide both sides by cos20° )

y = $\frac{11}{cos20}$ ≈ 11.71

Using the sine ratio on the right triangle on the left, that is

sin35° = $\frac{opposite}{hypotenuse}$ = $\frac{y}{x}$ = $\frac{11.71}{x}$

Multiply both sides by x

x × sin35° = 11.71 ( divide both sides by sin35° )

x = $\frac{11.71}{sin35}$ ≈ 20.42

5 0

3 years ago

Read 2 more answers

What is all the names for a in the expression 7ab + 3

shepuryov [24]

Answer:

b,d,f are the answers......

5 0

3 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago