Point A is in Quadrant I where the x and y are both positive.
Point B lies in between Quadrants II and III. Or it lies on the x-axis (If this is an option).
Answer:
-0.46
Step-by-step explanation:
We have small sample sizes n1 = 9 and n2 = 9. , ; , .
Because Carlos conducts a study comparing the performance of individuals on the first quiz in each of two classes taken in the first term of their freshman year, the hypothesis null is , then, the observed t-value is
The answer for the exercise shown above is the second option, the option B, which is: B. In step 3, the addition property of equality was applied incorrectly.
The explanation is:
To solve this problem you must apply the proccedure shown below:. You have the followinwg equation:
<span>
4(m-3)+5(m+2)=m+9
Let's review the steps:
4m-12+5m+10=m+9 (step 1)
9m-2=m+9 (step 2)
8m =7 (step 3) (There is a mistake, because: 9m-m=9+2</span>⇒8m=11)
<span> m=11/8 This should be the step 4</span>
Answer:
9,849
Step-by-step explanation:
AC = -1 - ( -5) = 4
BC = 4 - ( -5) = 9
AM^2 = AC^2 + BC^2
AM^2 = 4^2 + 9^2
AM^2 = 97
AM = sqrt(97)
AM = 9,849
Done