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Viktor [21]
3 years ago
7

Jan's age is 3 years less than twice Tritt's age. The sum of their ages is 30. Find their ages.

Mathematics
2 answers:
olganol [36]3 years ago
7 0
J - Jan's age
T - Tritt's age

(1) J + 3 = 2T
(2) J + T = 30    |subtract T from both sides
(2) J = 30 - T

subtitute (2) to (1)

30 - T + 3 = 2T
33 - T = 2T    |add T to both sides
3T = 33    |divide both sides by 3
T = 11

subtitute the value of T to (2)

J = 30 - 11
J = 19

Answer: Jan is 19 and Tritt is 11.
AysviL [449]3 years ago
5 0
J + t = 30
j = 2t - 3

sub eq 2 into eq 1
2t - 3 + t = 30...combine like terms
3t - 3 = 30...add 3 to both sides
3t = 30 + 3
3t = 33...divide both sides by 3
t = 33/3
t = 11 <=== Tritt is 11

j = 2t - 3
j = 2(11) - 3
j = 22 - 3
j = 19 <== Jan is 19
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The correct order would be:

5/64 x 3, 1/16 x 3, 3/32 x 4, 11/64 x 4, 7/16 x 3, 3/4 x 2, 3/8 x 4, 1 7/8 x 4, 2.25 x 2, 1.5 x 4, 3 3/8 x 3, 3.75 x 3

First we have to take all of the numbers and do the multiplication. It's often easiest to turn them in to decimals so that you have a common form.

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2.25 x 2 = 4.5

1.5 x 4 = 6

3/8 x 4 = 3/2 = 1.5

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Now we can use those to put in order.

5/64 x 3 = 5/32 = .156

1/16 x 3 = 3/16 = .1875

3/32 x 4 = 3/8 = .375

11/64 x 4 = 11/16 = .687

7/16 x 3 = 21/16 = 1.31

3/4 x 2 = 3/2 = 1.5

3/8 x 4 = 3/2 = 1.5

1 7/8 x 4 = 15/4 = 3.75

2.25 x 2 = 4.5

1.5 x 4 = 6

3 3/8 x 3 = 81/8 = 10.125

3.75 x 3 = 11.25

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