The acceleration due to gravity on the surface of Mars is about one third the acceleration due to gravity on Earth’s surface.

______ Made geocentric model of the solar system using epicycles

stiks02 [169]

Answer:

Ptolemy made geocentric model of the solar system using epicycles

Explanation:

Ptolemy made geocentric model of the solar system using epicycles.

This model accounted for the apparent motions of the planets in a very direct way, by assuming that each planet moved on a small circle, called an epicycle, which moved on a larger circle, called a deferent.

Therefore, Ptolemy is the answer.

3 0

3 years ago

What is the change in internal energy if 30 J of thermal energy is released

alexira [117]

Answer:

ΔU = -70 J

Explanation:

ΔU = Q − W

where ΔU is the change in internal energy,

Q is the heat absorbed by the system,

and W is the work done by the system (on the surroundings).

30 J of thermal energy is released, so Q = -30 J.

40 J of work is done by the system, so W = 40 J.

Therefore, the change in internal energy is:

ΔU = -30 J − 40 J

ΔU = -70 J

6 0

3 years ago

I rent a small high pressure water sprayer to clean the outside of my house. The sprayer works like a super soaker with a hose b

viva [34]

Answer:

1. 80,000 Pa

2. 11.3 m/s

3. 12.5 m/s

Explanation:

<u>Question 1</u>

Pressure, $P=hg\rho$

Where h is the height that water is to reach, g is gravitational constant and $\rho$ is the density, in this case, we assume $\rho$ of pure water as $1000 Kg/m^3$

Assuming $g=10 m/s^{2}$

P=8*10*1000=80000 Pa

<u>Question 2</u>

Pressure can also be found by the formula

$P=0.5v^{2}\rho$ where v is the velocity

Equating the new formula of pressure to the formula used in question 1 above

$P=0.5v^{2}\rho=hg\rho$

Notice that $\rho$ is common hence

$0.5v^{2}=hg$

Making V the subject of the formula

$v^{2}=2hg$

$v=\sqrt 2hg$

In this case, h=8-1.6=6.4m and taking g as 10 m/s^{2}

$v=\sqrt 2*10*6.4=11.3137085 m/s$

Rounding off to 1 decimal place

v=11.3 m/s

<u>Question 3</u>

As already illustrated

$v=\sqrt 2hg$

Taking g as 9.8 and h now is 8m

$v=\sqrt 2*8*9.8$

v=12.52198067

Rounding off to 1 decimal place

v=12.5 m/s

6 0

3 years ago

A ball of mass 0.200kg with a velocity of 1.50i^m/s meets a ball of mass 0.300kg with a velocity of -0.400 i^ m/s in a head-on,

Monica [59]

Velocities of their center of mass after collisions are found by the following formula as shown in the image:

<h3>What are elastic collisions?</h3>

An elastic collision is one in which there is no energy lost during the impact. A moderately inelastic collision occurs when some energy is wasted yet the items do not cling together. The maximum amount of energy is wasted when the objects collide in a perfectly inelastic impact. The kinetic energy doesn't change.
It may be two dimensions or one dimension. Because there will always be some energy exchange, no matter how tiny, totally elastic collision is not conceivable in the real world.
While the overall system's linear momentum does not change, the individual momenta of the participating components do, and because these changes are equal and opposite in size and cancel each other out, the initial energy is conserved.

To learn more about Elastic collisions refer to:

brainly.com/question/2356330

#SPJ4

4 0

2 years ago

. Using your knowledge of circular (centripetal) motion, derive an equation for the radius r of the circular path that electrons

Ronch [10]

Answer:

Explanation:

Magnetic field creates a force perpendicular to a moving charge in its field which is equal to Bev where B is magnetic field , e is amount of charge on the moving charge and v is the velocity of charge particle .

This force provides centripetal force for creation of circular motion. If r be the radius of the circular path

Bev = mv² / r

r = mv / Be

2 ) If an electron is accelerated by an electric field created by potential difference V then electric field

= V / d where d is distance between two points having potential difference v .

force on charged particle

electric field x charge

= V /d x e

work done by field

= force x distance

= V /d x e x d

V e

This is equal to kinetic energy created

V e = 1/2 mv²

= 1/2 m (r²B²e² / m² )

V = r²B²e/ 2 m

e / m = 2 V/ r²B²

3 )

B = $\frac{\mu\times I\times R^2}{2(R^2+Z^2)^\frac{3}{2} }$

In Helmholtz coils , distance between coil is equal to R so Z = R/2

B = $\frac{\mu\times I\times R^2}{2(R^2+\frac{R^2}{4} )^\frac{3}{2} }$

For N turns of coil and total field due to two coils

B = $\frac{\mu\times I\times N}{R\times(\frac{5}{4})^\frac{3}{2} }$

= $\frac{\mu\times I\times N}{R}\times (\frac{4}{5})^\frac{3}{2}$

= 9.0 x 10^-7 NI/R

8 0

4 years ago