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4 years ago

What effect does the velocity of a rotating object have on the centripetal acceleration?

Physics

2 answers:

kipiarov [429]4 years ago

7 0

Answer:

as centripatal force acts upon an object moving at a circle in constant speed de force acts always inwards as de velocity of object is directed tangent to de circle de force can accelerate de object by changing its direction bt not actually de speed

alina1380 [7]4 years ago

5 0

The two quantities are closely related, but the cause/effect is the other way around.

-- The centripetal force is caused by something outside this discussion, not by the object.

-- The centripetal force acting on the object determines the object's centripetal acceleration.

-- The centripetal acceleration is the cause of whatever the object's velocity (speed and direction) turns out to be.

-- It's the centripetal acceleration that has the effect on the object's velocity.

As an example, you wouldn't say that the orbiting of a TV satellite is what causes the Earth's centripetal force that acts on it.

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What type of electrical cord has a ground? 3 pronged cord 2 pronged cord

Kisachek [45]

<h3>Answer: A) 3 pronged cord</h3>

Explanation:

One prong is known as the hot wire, where the electricity comes in, while the second prong is the neutral wire and electricity leaves. Recall that a circuit must be made for electrons to flow. This means that electrons enters your house through the transmission wires and then the electrons leave along the same lines they entered (just along a different wire).

This set up describes a 2 pronged cord. Adding a third prong allows for a grounding to happen. In the event of an electrical surge, when too many electrons are flowing, disaster is likely to happen without some kind of safety features. The grounding prong allows electrons to seek the ground. You can think of it like a drain in a bathtub when too much water gets in the tub.

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3 years ago

A rock is suspended by a light string. When the rock is in air, the tension in the string is 37.8 N. When the rock is totally im

dusya [7]

When the rock is suspended in the air, the net force on it is

∑ F₁ = T₁ - m₁g = 0

where T₁ is the magnitude of tension in the string and m₁g is the rock's weight. So

T₁ = m₁g = 37.8 N

When immersed in water, the tension reduces to T₂ = 32.0 N. The net force on the rock is then

∑ F₂ = T₂ + B₂ - m₁g = 0

where B₂ is the magnitude of the buoyant force. Then

B₂ = m₁g - T₂ = 37.8 N - 32.0 N = 5.8 N

B₂ is also the weight of the water that was displaced by submerging the rock. Let m₂ be the mass of the displaced water; then

5.8 N = m₂g ==> m₂ ≈ 0.592 kg

If one takes the density of water to be 1.00 g/cm³ = 1.00 × 10³ kg/m³, then the volume of water V that was displaced was

1.00 × 10³ kg/m³ = m₂/V ==> V ≈ 0.000592 m³ = 592 cm³

and this is also the volume of the rock.

When immersed in the unknown liquid, the tension reduces further to T₃ = 20.2 N, and so the net force on the rock is

∑ F₃ = T₃ + B₃ - m₁g = 0

which means the buoyant force is

B₃ = m₁g - T₃ = 37.8 N - 20.2 N = 17.6 N

The mass m₃ of the liquid displaced is then

17.6 N = m₃g ==> m₃ ≈ 1.80 kg

Then the density ρ of the unknown liquid is

ρ = m₃/V ≈ (1.80 kg)/(0.000592 m³) ≈ 3040 kg/m³ = 3.04 g/cm³

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3 years ago

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3 years ago

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Answer:

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3 years ago