A ball of mass 0.200kg with a velocity of 1.50i^m/s meets a ball of mass 0.300kg with a velocity of -0.400 i^ m/s in a head-on,
1 answer:
Velocities of their center of mass after collisions are found by the following formula as shown in the image:
<h3>What are elastic collisions?</h3>- An elastic collision is one in which there is no energy lost during the impact. A moderately inelastic collision occurs when some energy is wasted yet the items do not cling together. The maximum amount of energy is wasted when the objects collide in a perfectly inelastic impact. The kinetic energy doesn't change.
- It may be two dimensions or one dimension. Because there will always be some energy exchange, no matter how tiny, totally elastic collision is not conceivable in the real world.
- While the overall system's linear momentum does not change, the individual momenta of the participating components do, and because these changes are equal and opposite in size and cancel each other out, the initial energy is conserved.
To learn more about Elastic collisions refer to:
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The image of the 3 cables used to support the flower pot is not given so i have attached it.
Answer:
F_ab = 523.2 N
F_ac = 392.4 N
F_ad ≈ 762.7 N
Explanation:
First of all, let's Calculate the sum of forces around the z-axis.
But before then, we need to resolve the distances along the 3 axis to get;
1.5/√(1.5² + 2² + 1.5²) = 0.5145
Thus;
ΣF_z = 0;
(F_ad × 0.5145) - (40 × 9.81) = 0
Where;
(40 × 9.81) is the weight of the flower pot.
F_ad is the force in cable AD
Thus;
0.5145F_ad - 392.4 = 0
F_ad = 392.4/0.5145
F_ad ≈ 762.7 N
Now, let's do the same for the x-axis;
ΣF_z = 0;
Since x = 1.5, just like z was the same 1.5, we will adopt same resolved distance.
F_ac - F_ad(0.5145) = 0
Where F_ac is force in cable AC
F_ac = 762.7 × 0.5145
F_ac = 392.4 N
Lastly, for the y-axis;
ΣF_y = 0;
y is 2 and so, we need to recalculate the resolved distance.
F_ab - F_ad(2/√(1.5² + 2² + 1.5²)) = 0
Where F_ab is the force in cable AB
F_ab = 762.7 × 0.686
F_ab = 523.2 N
Answer:
6.05 m/s
Explanation:
In order for the puck to reach the top of the ramp, its initial kinetic energy must be equal to its final potential energy.
So we can write:
(1)
where
m = 100 g = 0.1 kg is the mass of the puck
v is the initial speed of the puck
is the acceleration due to gravity
h is the height of the ramp
Here we know that
d = 4.60 m is the length of the ramp
is the angle of the ramp
So its height is
So now we can re-arrange eq (1) to find the minimum speed of the puck: