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Rainbow [258]
3 years ago
15

Will give 20 pts! pls answer

Mathematics
2 answers:
Lena [83]3 years ago
8 0

It would be Felix:

5/4 = 1.25

Hope this helps!

Dmitrij [34]3 years ago
8 0
The answer would be B Felix
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What are the real and complex solutions of the polynomial equation? x^3-8=0. with imaginary numbers
seraphim [82]

Answer:

Solutions are 2,  -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

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Step-by-step explanation:

The real solution is x = 2:-

x^3 - 8 = 0

x^3 = 8

x = cube root of 8 = 2

Note that a cubic equation must have  a total of 3 roots ( real and complex in this case).  We can find the 2 complex roots by using the following identity:-

a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here  a = x and b = 2 so we have

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To find the complex roots we solve x^2 + 2x + 4 = 0:-

Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2

= -1 +/- (sqrt( -10)) / 2

= -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

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3 years ago
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Answer:

Step-by-step explanation:

I know that the two means are are 11.28 and 12.

I could be wrong but I did the math 5 times.

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