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Bad White [126]
3 years ago
15

Solve the following problems using ELIMINATION.

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

(4,10)

Step-by-step explanation:

   8x - 5y = -18

+  2x + 5y = 58

10x = 40

Dive both sides by 10.

x = 4

2x + 5y = 58

2(4) + 5y = 58

8 + 5y = 58

5y = 50

y = 10

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Answer:

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2 years ago
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Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

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3 0
1 year ago
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lozanna [386]

Answer:

j = $7.38 / 18

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3 0
3 years ago
Round 0.581 to the nearest tenth.
Furkat [3]
The answer is 0.6, 5 or higher add one more, 4 or less stays the same
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3 years ago
Find, in standard form l, the value of 59639÷0.087. Give your answer to 2sf.
marishachu [46]
Your answer should be 685505.75.
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4 years ago
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