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Julli [10]
3 years ago
8

If two polygons are similar the corresponding sides and angles are congruent

Mathematics
1 answer:
Solnce55 [7]3 years ago
8 0

Answer:

True

Step-by-step explanation:

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Free pts giveaway! :))
vredina [299]

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Hi

Step-by-step explanation:

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2 years ago
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Find the rate of increase:<br> Original amount: $2000<br> Final amount: $3000
Genrish500 [490]

Answer:

21

Step-by-step explanation:

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Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

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3 years ago
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Write the equation of a line perpendicular to y= -1/3x + 5 and passes through the point (6, 4).
Levart [38]

Answer:

y = 3x - 14

Step-by-step explanation:

Perpendicular lines will have a opposite reciprocal slope, so the slope will be 3.

Plug in the slope and given point into y = mx + b, then solve for b:

y = mx + b

4 = 3(6) + b

4 = 18 + b

-14 = b

Plug in the slope and y intercept into y = mx + b

y = 3x - 14

So, the equation of the line is y = 3x - 14

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Which table of values corresponds to the graph below?
mash [69]
I don’t know I can’t see the graph real well
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