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3 years ago

The diameter of a sphere is 4 centimeters. Which represents the volume of the sphere?

Mathematics

1 answer:

lord [1]3 years ago

7 0

Answer:

V = 33.5 cm^3

Step-by-step explanation:

The volume of a sphere is given by

V=4/3 pi r^3

The diameter is 4

r= d/2

r =4/2 =2

V = 4/3 pi (2)^3

V = 4/3 pi 8

V = 32/3 pi

Assuming pi is approximated by 3.14

V = 32/3 (3.14)

= 33.493333333 cm^3

To the nearest tenth

V = 33.5 cm^3

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Recall that a 6-bit string is a bit strings of length 6, and a bit string of weight 3, say, is one with exactly three 1's. How m

strojnjashka [21]

Answer:

1.. Total number of 6 bit strings is 64

2. Number of 6-bit strings with weight of 0 is 1

3. Number of 6-bit strings with weight of 1 is 6

4. Number of 6-bit strings with weight of 3 is 20

5. Number of 6-bit strings with weight of 5 is 6

6. Number of 6-bit strings with weight of 6 is 1

7. Number of 6-bit strings with weight of 7 is 0

Step-by-step explanation:

A bit string is a string that contains 0 and 1 only

1. Total number of 6 bit strings is 2^6 = 64

2. Number of 6 bit strings with weight 0 is 1

Explanation

Weight 0 means a string with no occurrence of 1

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 0 i.e. no occurrence of 1

6C0 = 6!/(6-0)!0!

6C0 = 6!/6!0!

6C0 = 1

Hence, the number of string with weight 0 (i.e. no occurrence of 1 ) is 1

3. Number of string with weight 1 is 6

Explanation

Weight 0 means a string with exactly 1 occurrence of '1'

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 1

6C1 = 6!/(6-1)!1!

6C1 = 6!/5!1!

6C1 = 6

Hence, the number of string with weight 6

4. Number of string with weight 3 is 20

Explanation

n = 6 and r = 3

6C3 = 6!/(6-3)!3!

6C3 = 6!/3!3!

6C3 = 20

Hence, the number of string with weight 3 is 20

5. Number of string with weight 5 is 6

Explanation

n = 6 and r = 5

6C5 = 6!/(6-5)!5!

6C5 = 6!/1!5!

6C5 = 6

Hence, the number of string with weight 5 is 6

6. Number of string with weight 6 is 1

Explanation

n = 6 and r = 6

6C6 = 6!/(6-6)!6!

6C6 = 6!/0!6!

6C6 = 1

Hence, the number of string with weight 6 is 1

7. Number of string with weight 7 is 0

Weight of 7 means that a string that has 7 occurrence of 1

The total length of a 6 bit is 6

Since 6 is less than 7, there's no way a bit of weight 7 can occur.

So, the right answer for this is 0.

8 0

3 years ago

What is 23 over 18 in simplest form

tatuchka [14]

$\frac{23}{18}$ is already in simplest form because 23 is a prime number, which means that it is only divisible by 1 and itself (23). Hope this helps! :)

6 0

3 years ago

What's the slope of 2,3 and 9,4

prohojiy [21]

Slope 1/7 ; easiest way to remember is rise over run

7 0

3 years ago

Write a polynomial in standard form that represents the area of the shaded region.

mr_godi [17]

Area of rectangle is $2x^2+x-45$

Step-by-step explanation:

Given:

Length of rectangle = 2x-9

Width of rectangle = x+5

Required:

Area of rectangle

Formula:

$Area\,\,of\,\,rectangle=Length*Width$

Putting values of length and width:

$Area\,\,of\,\,rectangle=Length*Width\\Area\,\,of\,\,rectangle=(2x-9)(x+5)\\Area\,\,of\,\,rectangle=2x(x+5)-9(x+5)\\Area\,\,of\,\,rectangle=2x^2+10x-9x-45\\Area\,\,of\,\,rectangle=2x^2+x-45$