All categories

3 years ago

The area of a regular octagon is 35 cm squared what is the area of a regular octagon with sides five times as long

Mathematics

2 answers:

KATRIN_1 [288]3 years ago

7 0

The answer would be 875cm squared

sashaice [31]3 years ago

6 0

So first, you must use the area of an octagon formula to find the length of one side of the given octagon...
A = 2 ( 1 + √2) s^2
35 = 2 ( 1 + √2) s^2
s = 2.57 cm

Next, you must use the area of an octagon formula to find the area of the second octagon by multiplying the side length above by five.
A = 2 ( 1 + √2) s^2
A = 2 ( 1 + √2) (2.57 • 5)^2
A = 736.44 cm^2

You might be interested in

The score with respect to par for one golfer: 1,+5 2,-2

Rasek [7]

Answer:

the answer or score of the golfer would be six

4 0

3 years ago

If Chris has 4 times as many nickels as quarters and they have a combined value of 180 cents, how many of each coin does he have

Oduvanchick [21]

82 to coins and quadrilateral

6 0

4 years ago

Read 2 more answers

Rashawn read 25 pages of his book each day until he finished the book. His book was 400 pages long.

Katyanochek1 [597]

The first thing we are going to do for this case is define variables.

We have then:

x: number of days

y: number of pages remaining.

We write the linear equation that models the problem:

$y = -25x + 400$

The intersection with the vertical axis is:

We evaluate x = 0:

$y = -25 (0) + 400\\y = 0 + 400\\y = 400$

We get the point:

$(x, y) = (0, 400)$

The intersection with the horizontal axis is:

We evaluate y = 0:

$0 = -25x + 400\\25x = 400$

$x = \frac{400}{25}\\x = 16$

We get the point:

$(x, y) = (16, 0)$

Answer:

The graph is:

$y = -25x + 400$

Graph located in the bottom left.

4 0

3 years ago

Read 2 more answers

A necklace has and matching bracelet have two types of beads. The necklace has 12 large beads and 8 small beads and weighs 88 gr

miv72 [106K]

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Step-by-step explanation:

Let,

Weight of one large bead = x

Weight of one small bead = y

According to given statement;

12x+8y=88 Eqn 1

5x+2y=25 Eqn 2

Multiplying Eqn 2 by 4

$4(5x+2y=25)\\20x+8y=100\ \ \ Eqn\ 3\\$

Subtracting Eqn 1 from Eqn 3

$(20x+8y)-(12x+8y)=100-88\\20x+8y-12x-8y=12\\8x=12$

Dividing both sides by 8

$\frac{8x}{8}=\frac{12}{8}\\x=1.5$

Putting x=1.5 in Eqn 1

$12(1.5)+8y=88\\18+8y=88\\8y=88-18\\8y=70$

Dividing both sides by 8

$\frac{8y}{8}=\frac{70}{8}\\y=8.75$

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

5 0

3 years ago

Required

Ludmilka [50]

Step-by-step explanation:

option c is correct not enough of information

as to calculate what was his change we have to calculate the sum of cost of each material he bought, and cost of six pack of diet mountain dew are missing, therefore option c is correct.

hope this answer helps you dear....take care and may u have a great day ahead!

4 0

3 years ago