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kkurt [141]
3 years ago
10

The area of a regular octagon is 35 cm squared what is the area of a regular octagon with sides five times as long

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
7 0
The answer would be 875cm squared
sashaice [31]3 years ago
6 0
So first, you must use the area of an octagon formula to find the length of one side of the given octagon...
A = 2 ( 1 + √2) s^2
35 = 2 ( 1 + √2) s^2
s = 2.57 cm

Next, you must use the area of an octagon formula to find the area of the second octagon by multiplying the side length above by five.
A = 2 ( 1 + √2) s^2
A = 2 ( 1 + √2) (2.57 • 5)^2
A = 736.44 cm^2
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Given that GI = 53, and
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We can establish the following equality statement to solve for x:

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Add 7 to both sides:
5x - 7 + 7 = 53 + 7
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Divide both sides by 5 to solve for x:
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Substitute the value of x into the equality statement to verify if it is the correct value for x:

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3(12) - 11 + 2(12) + 4 = 53
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Therefore:
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HI = 2(12) + 4
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