Oscar played games vs number of points he scored is, C) positive, linear association.
Step-by-step explanation:
- no association is when points Oscar graph will remain between 8to10.
- number of games he scored his points remain the same which is mean.
- non linear is only when there is no straight line passing.
- Linear is either exponential or polynomial.
- Positive as the game increase he scoring abilities increases.
- Negative as the game increases his scoring decreases.
- Negative x axis will have more number of points.
- Negative y axis will high to low of the graph.
- Linear lines are best way to predict a data doesn't work will all data.
Answer:
1436.76 in.^3
Step-by-step explanation:
This question means to find the volume of a sphere with a diameter of 14 inches. The formula for the volume of a sphere is 4/3πr^3, so we need to find the radius, which is half the diameter. Half of the diameter is 7 inches, so now we can plug in our values to find the volume is about 1436.76 cubic inches.
Answer:
The standard form as 
Step-by-step explanation:
Given: A function which is written in vertex form or intercept form.
We have to re-write it in standard form that in terms of
Given 
Squaring using 
, we get,
Multiply 5 inside , we get,
Solving further , we get,
Thus , we have obtained the standard form as
<span>The cube’s sides measures 6 inches and the measurement for
the rectangular box is that it is 10 inches long, 4 inches thick and 4 inches
high. To compute for the volume of a cube you must use the formula of V = a3
and for the rectangular prism is V = l x w x h.</span>
<span>Cube: V = 6^3
</span> <span>V = 216 inches^3</span>
<span>Rectangular Prism: V
= 10 x 4 x 4</span>
<span>
V
= 160 inches^3</span>
To identify how much greater the volume the cube from the
rectangular box we subtract their volumes.
N = C – R where N stands for the unknown C for the volume of
cube and R for the volume of Rectangular Box
<span>
N = 216 inches^3 – 160 inches^3
</span>
<span>N = 56 inches^3</span>
<span>
So the cube is 56 inches3 greater than the
rectangular box.</span>
This is true based on the theorem corresponding parts of congruent figures are congruent.
