Well the first equation has a variable in it while the other one doesn't also the first expression if set equal to 0 is -2 while the other one is 5
Answer:
Step-by-step explanation:
Given that there are two functions f and g as
We have to find the composition of functions.
Composition functions are calculated as the first function inside bracket and then the outside function of answer inside.
a)
b) 
c) ![fof = f(\sqrt{x} ) = \sqrt[4]{x}](https://tex.z-dn.net/?f=fof%20%3D%20f%28%5Csqrt%7Bx%7D%20%29%20%3D%20%5Csqrt%5B4%5D%7Bx%7D)
d) 
Answer:
1. 30(8.75) + 11t = 400
2. 12.5 hours
Step-by-step explanation:
1. What is given is you work for 30 hours per week at a gas station for $8.75 an hour. You also work as a landscaper for $11 an hour. You want to a make a total of $400 per week.
30 hours and $8.75 an hour would be equivalent to 30(8.75)
We don’t know how many hours you work as a landscaper but you earn $11 an hour, which is equivalent to 11t
Finally, you want to earn a total of $400 a week, which means the sum equals 400
30(8.75) + 11t = 400
2. 30(8.75) = 262.5
400 - 262.5 = 137.5
137.5 / 11 = 12.5
Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s
