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3 years ago

If there are 21 values in a data set in order from smallest to largest, what is the first quartile of the data set?

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

7 0

Answer with explanation:

Total Number of Variate in the Data set = 21

Since number of Variate is odd, median is given by the formula:

$=\frac{\text{Total number of terms}+1}{2}\\\\=\frac{21+1}{2}\\\\=11^{\text{th term}}$

$Q_{1}$

= Mid value between lowest Variate and Median value.

→→Mid value of first 11 Terms is given by

$=\frac{\text{Total number of terms}+1}{2}\\\\=\frac{11+1}{2}\\\\=6^{\text{th term}}$

Most Appropriate Option:⇒

Option A: →The mean of the 6th and 7th values

jek_recluse [69]3 years ago

4 0

I think the answer is B) The mean of the 5th and 6th values

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The crew on a fishing boat caught 4 fish that weighed a total of 1,092 pound. The tarpon weighed twice as much as the amberjack

Savatey [412]

ddddd

Let T be the weight of Tarpon

Let A be the weight of amberjack

Let W be the weight of white marlin

Let TU be the weight of Tuna

The crew on a fishing boat caught 4 fish that weighed a total of 1,092 pound.

Total weight = 1092

T + A + W + TU = 1092

The tarpon weighed twice as much as the amberjack

T= 2 A

the white marlin weighed twice as much as the tarpon.

W = 2 T

We know T is 2A so W = 2(2A) = 4 A, W = 4A

The weight of the tuna was 5 times the weight of the Amber jack.

TU = 5A

T = 2A , W = 4A , TU = 5A

Replace it in our equation

T + A + W + TU = 1092

2A + A + 4A + 5A = 1092

12A = 1092

Divide both sides by 12

A = 91

the weight of amberjack = 91 pounds

the weight of white marlin = 4A = 4(91) = 364 pounds

the weight of Tarpon = 2A = 2(91) = 182 pounds

the weight of Tuna= 5A = 5(91)=455 pounds

7 0

2 years ago

Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure

Marina CMI [18]

Answer:

a) $P(0.11$

And we can find this probability with this difference and with the normal standard table or excel:

$P(-1.11$

b) $P(0.11 < \bar X < 0.13)$

And we can use the z score defined by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using the limits we got:

$z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22$

$z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22$

And we want to find this probability:

$P(-2.22< Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

$X \sim N(0.12,0.009)$

Where $\mu=0.12$ and $\sigma=0.009$

We are interested on this probability

$P(0.11$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(0.11$

And we can find this probability with this difference and with the normal standard table or excel:

$P(-1.11$

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we want this probability:

$P(0.11 < \bar X < 0.13)$

And we can use the z score defined by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using the limits we got:

$z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22$

$z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22$

And we want to find this probability:

$P(-2.22< Z$

4 0

3 years ago

Read 2 more answers

a triangle has a perimeter of 10x+2 . two sides have lengths of 5x and 2x+9 what is the length of the 3rd side

stiks02 [169]

Since all the sides add up to 10x+2, that means that 10x-2-<side1>-<side2>=<side3>. Plugging it in, we have 10x-2-5x-(2x+9)=side3, and 5x-2-(2x+9)=side3, then expanding it to 5x-2-2x-9=3x-11=side3

8 0

3 years ago

Prism M and pyramid N have the same base area and the same height. Cylinder P and prism Q have the same height and the same base

m_a_m_a [10]

Answer:

Answer Cone Z and Cylinder Y.

Step-by-step explanation:

The relationship between the volume of the cone and the volume of the cylinder with the same height and same base is the volume of the cone is 1/3 of the volume of the cylinder.

The formula for the volume of the cone is :

V = 1/3π $r^{2}$ h