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kirza4 [7]
3 years ago
11

0.00037 in scientiific notation

Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

37x10^-4

Step-by-step explanation:

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PLZ ANSWER !!!!!!
erastova [34]

Answer:

289.877 ft

Step-by-step explanation:

You can draw the eagle and mouse by using a right triangle. You know that the height of the triangle will be 280 feet and the distance between eagle and mouse should be the hypotenuse. Since we know the angle and one side of the triangle, we can use trignometry (cosine(angle)=adjacent/hypotenuse). Plug in your values and solve for the hypotenuse.

5 0
3 years ago
A library had 570 books when it first opened. A year later, the number of books increased by 30%. How many books were there in t
s344n2d4d5 [400]

Answer: There were 741 books in the library a year later.

Step-by-step explanation:

Given: Total books in library = 570

Number of books increased by 30%.

One year later, Number of books in the library = (Total books in library) + 30% x (Total books in library)

= 570 + (0.30) x (570)

= 570 (1+0.30)

= 570 (1.30)

= 741

Hence, there were 741 books in the library a year later.

3 0
3 years ago
I need help please.
Ira Lisetskai [31]

Answer:

82.5 grams

Step-by-step explanation:

11*7.5=82.5

3 0
3 years ago
Can someone plss help me with this with good explanation!!!
LekaFEV [45]

Answer:

1. What happens when air is heated or cooled? ... So air, like most other substances, expands when heated and contracts when cooled. Because there is more space between the molecules, the air is less dense than the surrounding matter and the hot air floats upward.

Step-by-step explanation:

Hope this helps

7 0
2 years ago
Find the average value of the function f(t)=cos13(5t)sin(5t) f(t)=cos13⁡(5t)sin⁡(5t) on the interval [4,10].
Vilka [71]
The average value is given by

\displaystyle\frac1{10-4}\int_4^{10}\cos^{13}5t\sin5t\,\mathrm dt

Setting y=\cos5t, you get \mathrm dy=-5\sin5t\,\mathrm dt, and the integral becomes

\displaystyle-\frac1{30}\int_{\cos20}^{\cos50}y^{13}\,\mathrm dy
=-\dfrac1{30}\dfrac{y^{14}}{14}\bigg|_{y=\cos20}^{y=\cos50}
=-\dfrac{\cos^{14}50-\cos^{14}20}{420}\approx-0.00145
6 0
4 years ago
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