Ask question

Ask question

All categories

3 years ago

11

The measure of AngleRST can be represented by the expression (6x + 12)°. Three lines extend from point S. The space between line

s S R and S U is 78 degrees. The space between lines S U and S T is 3 x minus 12. What is mAngleRST in degrees?

1 answer:

DochEvi [55]3 years ago

8 0

Answer:The measure of angle RST is 120\°

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m<RST=(6x+12)\° -----> equation A

m<RST=78\°+(3x-12)\° -----> equation B

equate equation A and equation B

(6x+12)\°=78\°+(3x-12)\°

You might be interested in

Find the volume of the figure. Round your answer to the nearest tenth if necessary. Use 3.14 for .

sp2606 [1]

Answer:

$\boxed{\rm \: Volume_{(Cylinder)} \approx \: 307.7 \: m {}^{3} } ( \rm \: nearest \: tenth )$

Step-by-step explanation:

Given:

radius = 7 metres
height = 2 metres
π = 3.14

To Find:

Volume of the cylinder

Solution:

Use the formulae of the volume of cylinder:

$\boxed{\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h}$

where,

π = 3.14
r = radius
h = height

According to the question:

radius = 7 metres
height = 2 metres

Substitute the values onto the formulae in order to find out the volume:

$\rm \: Volume_{(Cylinder)} = \pi(7) {}^{2} (2)$

$\rm \: Volume_{(Cylinder)} = \pi(49)(2)$

$\rm \: Volume_{(Cylinder)} = 98\pi$

$\rm \: Volume_{(Cylinder)} = \: 98 \times 3.14$

$\rm \: Volume_{(Cylinder)} = 307.72 \: m {}^{3} \: (exact \: form)$

$\boxed{\rm \: Volume_{(Cylinder)} \approx \: 307.7 \: m {}^{3} } \: ( \rm nearest \: tenth )$

<u>Hence,we can conclude that:</u>

The volume of the cylinder is approximately

307.7m³.

8 0

2 years ago

What is 10 + 12 and what is 12 + 10

Sedbober [7]

Hi ^-^

Answer: for both it's 22

7 0

4 years ago

Read 2 more answers

Here are two squares, A and B. A B The length of each side of square B is 4cm greater than the length of each side of square A.

alina1380 [7]

Answer:

144cm²

Step-by-step explanation:

Area of square A Aa = La²

Area of square B Ab= Lb²

If the length of each side of square B is 4cm greater than the length of each side of square A, then;

Lb = La + 4 ... 1

Also if the area of square B is 70cm² greater than the area of square A, then;

Ab = Aa + 70

Since Aa = La² and Ab = Lb²

Lb² = La² + 70 ...2

Substitute 1 into 2;

(La+4)² = La²+70

Expand

La²+8La+16 = La²+80

8La+16 = 80

8La = 80 - 16

8La = 64

La = 64/8

La = 8cm

Since Lb = La + 4

Lb = 8 + 4

Lb = 12cm

Area of square B = Lb²

Area of square B = 12²

Area of square B = 144cm²

4 0

3 years ago

Read 2 more answers

Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2

zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

Step-by-step explanation:

Un par ordenado es un elemento de la forma $(x,f(x))$ , donde $x$ es un elemento del dominio de la función, mientras $f(x)$ es la imagen de la función evaluada en $x$ . Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

$x \rightarrow f(x)$

Dado que $f(x)$ es una función polinómica, existe una imagen para todo elemento $x$ . Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

$f(0) = 0^{3}-2\cdot (0)^{2}-2$

$f(0) = -2$

(0, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 1

$f(1) = 1^{3}-2\cdot (1)^{2}-2$

$f(1) = -3$

(1, -3) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 2

$f(2) = 2^{3}-2\cdot (2)^{2}-2$

$f(2) = -2$

(2, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 3

$f(3) = 3^{3}-2\cdot (3)^{2}-2$

$f(3) = 7$

(3, 7) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

6 0

3 years ago

Suppose the number 1155 is written as the product of three positive integers. What is the smallest possible value of the sum of

ozzi

3. the equation I used is: 3×5×77

6 0

3 years ago