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tigry1 [53]
3 years ago
9

Question 8 (2 points) 15 is 25% of Brank 1: HELPPP MEEE

Mathematics
2 answers:
Ilya [14]3 years ago
3 0

Answer:

15 is 25% of 60

Step-by-step explanation:

15 x 4 = 60

25% x 4 = 100%

ozzi3 years ago
3 0

Answer:

I think that might be 60

Step-by-step explanation:

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What is the square root of 50 rounded to the nearest tenth
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i think 10th: √ 50 ≈ 7.1 100th: √ 50 ≈ 7.07

Step-by-step explanation:

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Find the area of the figure below:
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288

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Rewrite 7 1/8 as an improper fraction.
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4 years ago
A machine that produces a major part for an airplane engine is monitored closely. In the past, 10% of the parts produced would b
nata0808 [166]

Answer:

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The margin of error:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

p = 0.1

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is

We need a sample size of at least n, in which n is found M = 0.04.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.1*0.9}{n}}

0.04\sqrt{n} = 0.588

\sqrt{n} = \frac{0.588}{0.04}

\sqrt{n} = 14.7

(\sqrt{n})^{2} = (14.7)^{2}

n = 216

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

7 0
4 years ago
There are 25 students in Laura's class, and 21 of the students went on the class trip to the zoo. What percentage of students we
BlackZzzverrR [31]
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7 0
3 years ago
Read 2 more answers
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