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tamaranim1 [39]
3 years ago
14

Solve for x in the diagram below.

Mathematics
2 answers:
svetoff [14.1K]3 years ago
6 0

Answer:

x = 20

Step-by-step explanation:

x and 3x + 10 form a right angle, then

x + 3x + 10 = 90

4x + 10 = 90 ( subtract 10 from both sides )

4x = 80 ( divide both sides by 4 )

x = 20

NemiM [27]3 years ago
3 0

Answer:

x = 20

Step-by-step explanation:

The sum of the two angles is 90 degrees

x+3x+10 = 90

Combine like terms

4x+10 = 90

Subtract 10 from each side

4x+10-10 = 90-10

4x= 80

Divide each side by 4

4x/4 = 80/4

x = 20

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Using a six-sided die, you have rolled a 6 on each of four successive tosses. What is the probability of rolling a 6 on the next
ollegr [7]

Answer:

The probability of rolling a 6 on the next toss = 1/6

Step-by-step explanation:

Given - Using a six-sided die, you have rolled a 6 on each of four successive tosses.

To find - What is the probability of rolling a 6 on the next toss?

Proof -

As the outcomes of previous rolls do not affect the outcomes of future rolls.

And there is one desired outcome and six possible outcomes.

So,

The probability of rolling a six on the fifth roll = 1/6 which is same as the probability of rolling a six on any given individual roll.

So,

The answer is -

The probability of rolling a 6 on the next toss = 1/6

8 0
3 years ago
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Step-by-step explanation:

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3 years ago
What are the real zeros of y=(x+3)^3+10
aivan3 [116]
<span> y - x3 - 9x2 - 27x - 37 = 0 is this what you were looking for?</span>
4 0
3 years ago
the teacher of a senior class needs to choose 4 members of the class to represent the school. if there are 10 seniors in the cla
3241004551 [841]
There are 10 seniors in the class, from which 4 should be chosen by the teacher. The order of the chosen students does not matter. This means that we speak of combinations. THe equation for calculating the number of possible combinations is:
C=N!/R!(N-R), where N is the total number of objects and R is the number of objects we select from the N 
In our case, N=10, R=4.
C= 10!/4!*6!=10*9*8*7*6!/6!*4*3*2*1=<span>10*9*8*7/24=5040/24=210
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6 0
3 years ago
They have a rectangle ABCD as shown below, where AB = 24cm BC = 10cm and AE = 13cm
alex41 [277]

Answer:

A. Area of ABCD = 240 cm^{2}

B. 60 cm

C. 36 cm

D. 50 cm

Step-by-step explanation:

Given: AB = 24cm BC = 10cm and AE = 13cm.

A.  Since a rectangle is a 2 dimensional figure, it has no volume but area.

So that,

the area of the rectangle ABCD = length x width

                                                     = 24 x 10

                                                     = 240 cm^{2}

B. To calculate the circumference of the BCD triangle, apply the Pythagoras theorem to determine BD.

BD^{2} = BC^{2} + DC^{2}

       = 10^{2} + 24^{2}

       = 676

BD = \sqrt{676}

     = 26

BD = 26 cm

so that,

the circumference of BCD = 10 + 24 + 26

                                         =   60 cm

C. To calculate the circumference of the BEC triangle,

AC = 26 cm, AE = 13 cm

CE = 26 - 13

     = 13 cm

CE = 13 cm

The circumference of the BEC triangle = 13 + 13 + 10

                                                                 = 36 cm

D. The circumference of the DEC triangle = 13 + 13 + 24

                                                                 = 50 cm

       

7 0
3 years ago
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