A rectangular playground has a perimeter of 2400 ft. If

1 answer:

5 0

Let x be the length, y be the width and p be the perimeter.
p = 2x + 2y
Since the length is 3 times the width
x = 3y
So,
2400 = 2(3y) + 2y
2400 = 6y + 2y
2400 = 8y
y = 300
Now plug y back in,
x = 3(300)
x = 900
The length is 900 ft and the width is 300 ft

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Let x be the speed of the first car, then (x + 10) is the speed of the second car.

We can write the equation by the condition of the problem:

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But is there a fee for the question?

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