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USPshnik [31]
3 years ago
15

Which statement is true?

Mathematics
1 answer:
Allushta [10]3 years ago
5 0
Im pretty sure it is the first one
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Write a paragraph proof.<br><br> Given: ∠T and ∠V are right angles.<br><br> Prove: ∆TUW ∆VWU
Veseljchak [2.6K]

Step-by-step explanation:

in ∆TUW & ∆VWU

∠UTW = ∠UVW (data / given)

WU = WU (common sides) ∠TWU = ∠VUW (TW//UV alternate∠ )

so ∆TUW & ∆VWU are congruent

8 0
3 years ago
Read 2 more answers
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
maks197457 [2]
F(g(x)) = [(-7x-8)/(x-1) - 8} / [(-7x - 8)/(x-1) + 7] =

[(-7x - 8 - 8(x-1)) / (x-1)] / [(-7x - 8 + 7(x-1)) / (x-1)] = (-15x) / (-15) = x.

g(f(x)) = [-7*(x-8)/(x+7) - 8] / [(x-8)/(x+7) - 1] =

[(-7x + 56 -8*(x+7)) / (x+7)] / [(x - 8 - (x + 7)) / (x+7)] = (-15x) / (-15) = x.

So since f(g(x)) = g(f(x)) = x we can conclude that f and g are inverses.
5 0
3 years ago
HELP ASAP PLEASEEEEEEEEEE
Andrew [12]

Given the recursive formula, each terms is five time the previous one.

This means that:

  • f(6) is 5 times f(5), which means f(6)=5f(5)
  • in turn, f(5) is 5 times f(4), so we have f(5)=5f(4). This means that f(6)=5f(5)=5\cdot 5f(4) = 25f(4)
  • Finally, f(4)=5f(3) So, substituting this back gives

f(6)=25f(4)=25\cdot 5f(3)=125f(3)

In general, since you have f(n)=5f(n-1), each time you compute a new term you multiply by a factor of 5, so if m=n+k, you have

f(m)=5^kf(n)

4 0
3 years ago
Hey can you please help me posted picture of question
puteri [66]
We have the following function:
 P (m) = m / 6 + 9
 Clearing m we have:
 m = 6 * (p-9)
 m= 6*p - 6*9
 Rewriting:
 m (p) = 6p-54
 Answer:
 
The inverse function for this case is given by:
 
m (p) = 6p-54
 
option A
5 0
3 years ago
Read 2 more answers
PLLLSSS ANSWER<br> how many terms in 7x+4+2x+3x+5
Serga [27]

Answer:

3(4x+3) or 12x + 9

Step-by-step explanation:

8 0
3 years ago
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