Step-by-step explanation:
in ∆TUW & ∆VWU
∠UTW = ∠UVW (data / given)
WU = WU (common sides) ∠TWU = ∠VUW (TW//UV alternate∠ )
so ∆TUW & ∆VWU are congruent
F(g(x)) = [(-7x-8)/(x-1) - 8} / [(-7x - 8)/(x-1) + 7] =
[(-7x - 8 - 8(x-1)) / (x-1)] / [(-7x - 8 + 7(x-1)) / (x-1)] = (-15x) / (-15) = x.
g(f(x)) = [-7*(x-8)/(x+7) - 8] / [(x-8)/(x+7) - 1] =
[(-7x + 56 -8*(x+7)) / (x+7)] / [(x - 8 - (x + 7)) / (x+7)] = (-15x) / (-15) = x.
So since f(g(x)) = g(f(x)) = x we can conclude that f and g are inverses.
Given the recursive formula, each terms is five time the previous one.
This means that:
is 5 times
, which means 
- in turn,
is 5 times
, so we have
. This means that 
- Finally,
So, substituting this back gives

In general, since you have
, each time you compute a new term you multiply by a factor of 5, so if
, you have

We have the following function:
P (m) = m / 6 + 9
Clearing m we have:
m = 6 * (p-9)
m= 6*p - 6*9
Rewriting:
m (p) = 6p-54
Answer:
The inverse function for this case is given by:
m (p) = 6p-54
option A
Answer:
3(4x+3) or 12x + 9
Step-by-step explanation: