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3 years ago

Which statement is true?

Mathematics

1 answer:

Allushta [10]3 years ago

5 0

Im pretty sure it is the first one

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Write in scienctific notation .00000758

goldenfox [79]

Answer:

= 7.58 × 10-6

4 0

3 years ago

Read 2 more answers

rectangle ABCD is graphed in the cordinate plane. The following are the verticies of the rectangle; A(-6,-4),B(-4,-4),C(-4,-2),

Sholpan [36]

Answer:

Therefore Perimeter of Rectangle ABCD is 4 units

Step-by-step explanation:

Given:

ABCD is a Rectangle.

A(-6,-4),

B(-4,-4),

C(-4,-2), and

D (-6,-2).

To Find :

Perimeter of Rectangle = ?

Solution:

Perimeter of Rectangle is given as

$\textrm{Perimeter of Rectangle}=2(Length+Width)$

Length = AB

Width = BC

Now By Distance Formula we have'

$l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting the values we get

$l(AB) = \sqrt{((-4-(-6))^{2}+(-4-(-4))^{2} )}$

$l(AB) = \sqrt{((2)^{2}+(0)^{2} )}=2\ unit$

Similarly

$l(BC) = \sqrt{((-4-(-4))^{2}+(-2-(-4))^{2} )}$

$l(BC) = \sqrt{((0)^{2}+(2)^{2} )}=2\ unit$

Therefore now

Length = AB = 2 unit

Width = BC = 2 unit

Substituting the values in Perimeter we get

$\textrm{Perimeter of Rectangle}=2(2+2)=2(4)=8\ unit$

Therefore Perimeter of Rectangle ABCD is 4 units

8 0

3 years ago

What is the length of the longer side ?

Alexandra [31]

It’s probably 22 because 5 is on two sides and 11 is on two sides so 11 + 11+ 5+5 = 32

6 0

2 years ago

una ventana rectangular tiene l metros de ancho y h metros de altura, con un perímetro de 6 metros y un área de 2m² ¿cuál es la

seropon [69]

Answer:

The formula for calculating the width of the window is

$w=\frac{-(-3)(+/-)\sqrt{-3^{2}-4(1)(2)}} {2(1)}$

Step-by-step explanation:

The question in English is

A rectangular window is l meters wide and h meters high, with a perimeter of 6 meters and an area of 2m². What is the formula for calculating the width of the window?

we know that

The perimeter of the window is equal to

$P=2(l+w)$

we have

$P=6\ m$

$6=2(l+w)$

simplify

$3=(l+w)$

isolate the variable l

$l=3-w$ ----> equation A

The area of the window is equal to

$A=lw$

we have

$A=2\ m^2$

$2=lw$ ----> equation B

substitute equation A in equation B

$2=(3-w)w$

solve for w

$2=3w-w^2$

$w^2-3w+2=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$w^2-3w+2=0$

$a=1\\b=-3\\c=2$

substitute in the formula

$w=\frac{-(-3)(+/-)\sqrt{-3^{2}-4(1)(2)}} {2(1)}$ ---> formula for calculating the width of the window

$w=\frac{3(+/-)\sqrt{1}} {2}$

$w=\frac{3(+/-)1} {2}$

$w=\frac{3(+)1} {2}=2\ m$

$w=\frac{3(-)1} {2}=1\ m$

7 0

3 years ago

28 patients for 2 nurses

alukav5142 [94]

14 patients for each nurse

6 0

2 years ago