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Arisa [49]
3 years ago
8

Please help me for brainiest):):):):):):

Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

You can find 0.5% of a number by multiplying the number by

Step-by-step explanation:

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Find all solutions of each equation on the interval 0 ≤ x<2π.
Aleksandr [31]

Answer:

x = 0 \: or \:x =   \pi

Step-by-step explanation:

The given equation is

\tan^{2} (x) \sec^{2} (x)  + \sec^{2} (x)  - \tan^{2} (x) =  2

Subtract 2 from both sides and factor by grouping to get:

\sec^{2} (x)(\tan^{2} (x) + 2)  -1( \tan^{2} (x)  +  2)

(\tan^{2} (x) + 2) (\sec^{2} (x) - 1) = 0

By the zero product principle:

(\tan^{2} (x) + 2) = 0 \: or \:  (\sec^{2} (x) - 1) = 0

(\tan^{2} (x)  =  - 2 \: or \:  \sec^{2} (x)  =  1

When

\sec^{2} (x)  =  1 \implies\cos^{2} (x)  =  1

\implies \:  \cos(x)  =  \pm1

This implies

x = 0 \: or \:x =   \pi

When

{ \tan }^{2} (x) =  - 2

We have

\tan(x)  =  \pm \sqrt{ - 2}

hence x is not defined for all real numbers

6 0
3 years ago
Read 2 more answers
What does this mean: 70°20'
timurjin [86]
70 degrees, 20 minutes.   It's an angle measure in Degrees-Minutes-Seconds(DMS) instead of Decimal Degrees (DDS). DMS is commonly used in engineering, land survey and navigation for ships and planes.  

There are 60 seconds in one minute and 60 minutes in one degree.
So 70°20' is = 70\frac{20}{60}deg \approx70.33deg
8 0
3 years ago
Identify the domain of the function shown in the graph.
BARSIC [14]

x \geqslant 0
D
5 0
3 years ago
Read 2 more answers
8. (01.02)
aniked [119]

Answer:

51.

Step-by-step explanation:

f(x) = x^2 + 2x + 3 and g(x) = x + 4.

f(g(x)) = (x + 4)^2 + 2(x + 4) + 3

= x^2 + 4x + 4x + 16 + 2x + 8 + 3

= x^2 + 8x + 16 + 2x + 11

= x^2 + 10x + 27.

x = 2.

f(g(2)) = 2^2 + 10 * 2 + 27

= 4 + 20 + 27

= 31 + 20

= 51.

Hope this helps!

4 0
3 years ago
Read 2 more answers
2. Harry is rolling a die, what is the probability of him rolling an even
Yuri [45]

Answer:

1/2 ( equally likely and equally unlikely)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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