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adell [148]
2 years ago
13

Complete the equation of the line through (-6,-5) (−4,−4) PLZ HELP !!!

Mathematics
1 answer:
bogdanovich [222]2 years ago
6 0

Answer: y=1/2x−2

Step-by-step explanation:

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S and T are two-digit positive integers that have the same digits but in reverse order. If the positive difference between S and
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Answer :Answer: Did you get helped on this one?          

Step-by-step explanation: okay yup yup have a good day OKAY

Step-by-step explanation: HAVE A GOOD ONE OKAY

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Find the solution set for this equation:<br> -a2+4a=0<br> (Separate the two values with a comma)
Rashid [163]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: \{ 0,4 \}

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: -  {a}^{2}  + 4a = 0

\qquad \tt \rightarrow \: - ( {a}^{2}  - 4a) = 0

\qquad \tt \rightarrow \: {a}^{2}  - 4a = 0

\qquad \tt \rightarrow \:a(a - 4) = 0

The two cases are :

  • a = 0

or

  • a -4 = 0, that leads to a = 4

We can conclude :

\qquad \tt \rightarrow \:solution \: (a)  = \{ 0,4\}

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

5 0
2 years ago
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What is the greatest negative value of x such that the square root of 50-x<br> is an integer?
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It should be negative one  (-1)





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How do you do this Problem using factoring (fx)=4x^2-25?
Yanka [14]

Answer: (2x+5)(2x−5)

Step-by-step explanation:For me, what i like to do is to try divide the problem into two parts. For example in this problem, you would divide the 4x^2 into two 4x(since 4x+4x = 4x^2). Then 25 can be divide into into 5s (5x5=25). SInce you know that its a negative 25, you know that it has to be a negative on one of the sides. So the answer in factor form is (2x+5)(2x−5)

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The product of 2x^2+6x-8 and x+3 in standard form
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Answer:

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Step-by-step explanation:

(2x² + 6x - 8)(x + 3)                         Distribute

2x³ + 6x² + 6x² + 18x - 8x - 24      Combine like terms

2x³ + 12x² + 10x - 24                      This expression is in standard form

If this answer is correct, please make me Brainliest!

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