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LekaFEV [45]
3 years ago
12

20 points. MAY YOU HELP FAST PLEASE? The thing ends tonight.

Mathematics
1 answer:
deff fn [24]3 years ago
7 0

2) cant help here

3) b

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Tobias rented a kayak from a sports equipment store.
Ket [755]

Answer:

B

Step-by-step explanation:

Let x = every day he rented the kayak

Since the store charges $60 for each day, multiply x by 60 like this: 60x

They also have $25 on top of that; 60x + 25

This all has to equal $325; 60x + 25 = 325

To solve for x, subtract 25 from both sides

60x + 25 = 325

       - 25    - 25

60x = 300

Divide both sides by 60

60x/60 = 300/60

x = 5

This means Tobias rented the kayak for 5 days

7 0
3 years ago
A keycode must contain 2 letters and 3 numbers. The letters may be any letter of the alphabet. The numbers should be any number
OverLord2011 [107]
The English alphabet contains 26 letters (a, b, c, ...y, z). 

The digits from 0 to 9 are a total of 10.


A keycode contains 2 letters, and 3 numbers, for example:

AB 598;  MM 139;    NT 498; ...


So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of 

26*26=676 possible pairs of letters.


Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :

10*10*10=1,000 possible triples of numbers.


Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of 

676*1,000=676,000 keycodes.


Answer: 676,000
8 0
3 years ago
Read 2 more answers
What are two equivalent equations for<br> x(5x-6)+13x-10
Naily [24]
5x^2 +7x -10

5x^2 (-6x + 13x) - 10
4 0
3 years ago
Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val
Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

A(t) = Pe^{rt}

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that P = 330

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

A(t) = Pe^{rt}

590 = 330e^{8r}

e^{8r} = \frac{590}{330}

e^{8r} = 1.79

Applying ln to both sides:

\ln{e^{8r}} = \ln{1.79}

8r = \ln{1.79}

r = \frac{\ln{1.79}}{8}

r = 0.0726

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

A(t) = 330e^{0.0726t}

A(10) = 330e^{0.0726*10} = 682

The value of the account in the year 2009 will be $682.

4 0
4 years ago
A spring is attatched at one end to support B and at the other end to collar A, as represented in the figure. Collar A slides al
m_a_m_a [10]

Step-by-step explanation:

cos θ = 3 / AB

When θ = 28°:

cos 28° = 3 / AB

AB = 3 / cos 28°

AB ≈ 3.4

When AB = 5.2:

cos θ = 3 / 5.2

θ = cos⁻¹(3 / 5.2)

θ ≈ 54.8°

3 0
3 years ago
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