Answer: For the equation simply substitute 30 in for v and 4 in for s in the equation given, so H=-16t^2+30t+4
Part 2.
If the juggler misses the ball, you wish to know the time that it takes for the ball to travel the four feet from his hand to the ground, so respectively,
4=-16t^2+30t+4 or 0=-16t^2+30t or 0 = -16t+30,
solving for t, t =30/16 seconds or 1.875 seconds
Step-by-step explanation:
Remember, you take 1/2 of b and square it to get c
c=100
(b/2)^2=c
(b/2)^2=100
sqrt oth sides
b/2=+/-10
times both sides by 2
b=+/-20
it is 20 or -20
answe ris B
yo is right
Answer:
width =4.5ft
length=6ft
Step-by-step explanation:
w = x
L = 2x-3
area = L*w
27 = x(2x-3)
2x(x+3)-9(x+3)=0
(2x-9)(x+3)=0
2x-9=0
2x=9
x=9/2
x=4.5
L=2x-3=2*4.5-3 =9-3=6
Answer:a) L.C.M OF 2,3,5 is 30
THEREFORE=60/30+15/30÷10/30-6/30
=60/30+15/30×30/10-6/30(DMAS)
=60/30+3/2-6/30
=60+45/30 -6/30(ADDITION FIRST THEN SUBTRACTION.
=105/30-6/30
=105-6/30
=99/30
=33/10
b)(3+1/2)÷(2-1/2)=L.C.M IS 2,=(6+1/2)÷(4-1/2)=7/2÷3/2=7/3
Greetings from Brasil...
Let's apply the given formula:
A = (1/2)·B·H
The base of this polygon (in this case, the triangle) is B
B = X² - 2X + 6
The height of this polygon is H and is H
H = X + 4
Applying these values (B and H) in the given formula.....
A = (1/2)·B·H
A = (1/2)·(X² - 2X + 6)·(X + 4)
A = (1/2)·(X³ + 2X² - 2X + 24)
A = (X³/2) + X² - X + 12
OR
A = (X³ + 2X² - 2X + 24)/2
