Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.

To convert into decimal, move the decimal to the left by 6 positions.
It will be 0.00000563
Answer is A.
Yes it is because 4+4=8 and 8 is larger than 7
Answer:
A = 12 units ^2
Step-by-step explanation:
The area of the trapezoid is found by
A = 1/2 (b1+b2)h
b1 = 2
b2 = 4
h = 4
I found these by looking at the graph
A = 1/2(2+4) 4
A = 1/2(6*4)
A = 12 units ^2
A. Noncolinear
ABE although they are in the same side, but they don't lie on the same line.
so its a noncolinear.