Answer: The total number of logs in the pile is 6.
Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.
We are to find the total number of logs in the pile.
Let n represents the total number of logs in the pile.
Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with
first term, a = 32 and common difference, d = -6.
We know that
the n-th term of an arithmetic sequence with first term a and common difference d is
Since there are n logs in the pile, so we get
Thus, the total number of logs in the pile is 6.
Answer:
19th term = ar^18
19th term = 774,840,978
Step-by-step explanation:
First term, a = 2
Common ratio, r = 3
nth term of a geometric sequence = ar^(n-1)
19th term = ar^(19-1)
19th term = ar^18
= 2 × 3^18
= 2 × 387,420,489
= 774,840,978
19th term = 774,840,978
Answer:
m<1 = 39°
m<3 = 180-90-39= 51°
Step-by-step explanation:
Lines AC and DB are diagonals and always meet at right angles.
Kites have two sets of equivalent adjacent sides and one set up of congruent opposite angles.
Answer:
Step-by-step explanation:
surface area=area of sides +area of top and bottom
=2(4+5)×8+2×(4×5)
=2[(9×8)+20]
=2[72+20]
=2×92
=184 m²