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Mandarinka [93]
3 years ago
5

What number should go in the space? Multiplying by 1.98 is the same as increasing by _____%.

Mathematics
1 answer:
sattari [20]3 years ago
4 0
1.98
1.98*100
198

Multiplying by 1.98 is the same as increasing by 198%.
You might be interested in
Given f (x) = x2 + 5x + 6, what is f of the quantity 2 plus h end quantity minus f of 2 all over h equal to?
scoray [572]

We want to get the difference quotient for the given function, we will get see that the difference quotient is equal to:

f'(x) = 2x + 5

<h3>The difference quotient:</h3>

For a given function f(x), we define the difference quotient as:

\lim_{h \to 0}  \frac{f(x + h) - f(x)}{h}

In this case, we have:

f(x) = x^2 + 5x + 6

Replacing that in the difference quotient we get:

\lim_{h \to 0}  \frac{(x + h)^2 + 5*(x + h) + 6 - x^2 - 5x - 6}{h}\\\\\lim_{h \to 0}  \frac{x^2 + 2xh + h^2 + 5*x + 5*h + 6 - x^2 - 5x - 6}{h}\\\\\lim_{h \to 0}  \frac{ 2xh + h^2 + 5*h }{h}\\

Now we can cancel the factor h to get:

\lim_{h \to 0}  2x + h + 5 = 2x + 0 + 5 = 2x + 5

So the difference quotient is equal to 2x + 5.

If you want to learn more about difference quotients, you can read:

brainly.com/question/4224465

5 0
3 years ago
Suppose a person eats 2000 food calories on average per day. Note that 1 calorie= 4.184 joules and a food calorie = 1000 calorie
Crazy boy [7]

Answer: 0.097\text{\ J/s}

Step-by-step explanation:

Given :  1 calorie= 4.184 joules

A food calorie = 1000 calories = 4184 joules.

Then, 2000 food = 2\times4184=8368 joules   [By Unitary method]

We know that : \text{Power}=\dfrac{\text{Energy}}{\text{Time}}

Since 1 day = 24 hours

and 1 hour = 3600 seconds

Then, 24 hours = 24\cdot3600=86400 seconds.

Now,   \text{Power}=\dfrac{8368}{86400}

=0.0968518518519\approx0.097\text{\ J/s}

Hence, the average power of this intake = 0.097\text{\ J/s}

6 0
3 years ago
An equation for loudness L in decibels is given by L= 10LogR where R is the sound’s relative intensity. An air-raid siren can re
bazaltina [42]
We are asked to find ratio of two relative intensities. Let's start by rearranging formula for R:
L=10logR \\ logR= \frac{L}{10}   \\ applying formula  \\log_{a}b=c =\ \textgreater \ b= a^{c}\\R= 10^{\frac{L}{10}}

For air-raid siren we have:
R_{1}= 10^{\frac{150}{10}} =10^{15}
For jet engine noise we have:
R_{2}= 10^{\frac{120}{10}} =10^{12}

To find out <span>many times greater is the relative intensity of the air-raid siren than that of the jet engine noise we need to divide these two numbers:
</span>tex] \frac{R_{1}}{R_{2}} = \frac{10^{15}}{10^{12}} =10^{3}=1000[/tex]
4 0
3 years ago
16. Find the value of y. ​
devlian [24]

y + (2x -12) = 180 (since they are supplementary angles)

(2x-12) = 96 ( since they are alternate exterior angle)

2x = 96 + 12

2x = 108

x = 108/2

x = 54.

y+( 2x-12)=180

y+(2× 54 -12) = 180

y + (108-12) = 180

y + 96 = 180

y= 180-96

y = 84.

8 0
3 years ago
Khalil has a game board as shown below, which is a square with 20 cm sides. The area of the largest circle is 314
Elenna [48]

Answer:

The probability of scoring 1, 3, or 5 points with one randomly thrown dart is equal to divide the area of the largest circle by the area of the square game board

step 1:

Find the area of the square game board

"A=b^{2}"

we have

b=20cm

"substitute"

A=20^{2}

=400cm²

step 2:

Find the probability

P=314/400

=0.785

=0.785 x 100

=78.5%

4 0
3 years ago
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