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sattari [20]
3 years ago
5

Why hasn't net neutrality been taken away? It's past Dec 14.

Computers and Technology
1 answer:
Roman55 [17]3 years ago
6 0
Because it was only passed, now they have to decide what they want to do 
You might be interested in
in java how do i Write a program that reads a set of integers, and then prints the sum of the even and odd integers.
hammer [34]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to take input from user

public class Main{

public static void main(String[] args) { //start of main function

Scanner input = new Scanner(System.in); // creates Scanner class object  

       int num, integer, odd = 0, even = 0; //declare variables

       System.out.print("Enter the number of integers: "); //prompts user to enter number of integers

       num = input.nextInt(); //reads value of num from user

       System.out.print("Enter the integers:\n"); //prompts user to enter the integers

       for (int i = 0; i < num; i++) { //iterates through each input integer

           integer = input.nextInt(); // reads each integer value

               if (integer % 2 == 0) //if integer value is completely divisible by 2

                   even += integer; //adds even integers

               else //if integer value is not completely divisible by 2

                   odd += integer;  } //adds odd integers

           System.out.print("Sum of Even Numbers: " + even); //prints the sum of even integers

           System.out.print("\nSum of Odd Numbers: " + odd);//prints the sum of odd integers

           }}

Explanation:

The program is explained in the comments mentioned with each line of the code. I will explain the logic of the program with the help of an example.

Suppose user wants to input 5 integers. So,

num = 5

Suppose the input integers are:

1, 2 , 3, 4, 5

for (int i = 0; i < num; i++)  is a for loop that has a variable i initialized to 0. The condition i<num is true because i=0 and num=5 so 0<5. Hence the statements inside body of loop execute.

At first iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 1

if (integer % 2 == 0) checks if integer is completely divisible by 2. The modulo operator is used which returns the remainder of the division and if this remainder is equal to 0 then it means that the integer is completely divisible by 2 and if the integer is completely divisible by 2 then this means the integer is even. 1%2 returns 1 so this means this condition evaluates to false and the integer is not even. So the else part executes:

odd += integer;   this becomes:

odd = odd + integer

odd = 1

Now the value of i is incremented to 1 so i=1

At second iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 2

if (integer % 2 == 0) checks if integer is completely divisible by 2. 2%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even += integer;   this becomes:

even= even+ integer

even = 2

Now the value of i is incremented to 1 so i=2

At third iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 3

if (integer % 2 == 0) checks if integer is completely divisible by 2. 3%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd += integer;   this becomes:

odd= odd + integer

odd= 1 + 3

odd = 4

Now the value of i is incremented to 1 so i=3

At fourth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 4

if (integer % 2 == 0) checks if integer is completely divisible by 2. 4%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even+= integer;   this becomes:

even = even + integer

even = 2 + 4

even = 6

Now the value of i is incremented to 1 so i=4

At fifth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 5

if (integer % 2 == 0) checks if integer is completely divisible by 2. 5%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd+= integer;   this becomes:

odd= odd+ integer

odd= 4 + 5

odd = 9

Now the value of i is incremented to 1 so i=5

When i=5 then i<num condition evaluate to false so the loop breaks. The next two print statement prints the values of even and odd. So

even = 6

odd = 9

Hence the output is:

Sum of Even Numbers: 6                                                                                                           Sum of Odd Numbers: 9  

6 0
3 years ago
Drag each statement to the correct location.
VMariaS [17]

Answer:

(a)\ 222_{10} = DE_{16} --- True

(b)\ D7_{16} = 11010011_2 --- False

(c)\ 13_{16} = 19_{10} --- True

Explanation:

Required

Determine if the statements are true or not.

(a)\ 222_{10} = DE_{16}

To do this, we convert DE from base 16 to base 10 using product rule.

So, we have:

DE_{16} = D * 16^1 + E * 16^0

In hexadecimal.

D =13 \\E = 14

So, we have:

DE_{16} = 13 * 16^1 + 14 * 16^0

DE_{16} = 222_{10}

Hence:

(a) is true

(b)\ D7_{16} = 11010011_2

First, convert D7 to base 10 using product rule

D7_{16} = D * 16^1 + 7 * 16^0

D = 13

So, we have:

D7_{16} = 13 * 16^1 + 7 * 16^0

D7_{16} = 215_{10}

Next convert 215 to base 2, using division rule

215 / 2 = 107 R 1

107/2 =53 R 1

53/2 =26 R1

26/2 = 13 R 0

13/2 = 6 R 1

6/2 = 3 R 0

3/2 = 1 R 1

1/2 = 0 R1

Write the remainders from bottom to top.

D7_{16} = 11010111_2

<em>Hence (b) is false</em>

(c)\ 13_{16} = 19_{10}

Convert 13 to base 10 using product rule

13_{16} = 1 * 16^1 + 3 * 16^0

13_{16} = 19

Hence; (c) is true

7 0
2 years ago
Design and implement a class called Sphere that contains instance data that represent the sphere’s diameter. Define the Sphere c
Zolol [24]

Answer:

Import java.awt.*;

import java.util.*;

public class Sprhere

{// Instance Data private double surfaceA, volume, r, diameter; //Constructors public Sphere ()

{r = 0;diameter = 0; surfaceA = 0;volume = 0;}

public Sphere (double radius, double d, double SA, double v)

{this. r = radius; this. diameter = d; this. surfaceA = SA;this.volume = v;}

//--------------------------------------------------------------------// Accesors.//--------------------------------------------------------------------public double get Radius()

{return r;}

public double get Diameter()

{return diameter;}

public double get SurfaceA()

{return surfaceA;}

public double get Volume()

{return volume;}

//--------------------------------------------------------------------// Mutators.//--------------------------------------------------------------------

3 0
3 years ago
How many residues separate amino acids that are stabilized by hydrogen bonds in α helices?.
irina [24]

The numbers of residues separate amino acids that are stabilized by hydrogen bonds in α helices is  3.6 amino acid residues.

<h3>Why are amino acids called residues?</h3>

The  Amino acids are known to be compounds that are said to be called residues if there is  two or more amino acids that are known to be bond with each other.

Note that the amino group on one amino acid is one that tends to interacts with the carboxyl group and as such  form a peptide bond.

Therefore, The numbers of residues separate amino acids that are stabilized by hydrogen bonds in α helices is  3.6 amino acid residues.

Learn more about amino acids from

brainly.com/question/2526971

#SPJ1

5 0
1 year ago
What happens when you press the Enter key at the end of a line of bulleted text?
sladkih [1.3K]

i think the  answer is d

6 0
3 years ago
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