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d1i1m1o1n [39]
3 years ago
10

The cost to mail a package is $7 for the first 2 pounds and 30 cents for each additional ounce. Which of the following functions

represents the cost to mail a package if x is the number of ounces over 2 pounds? ƒ(x ) = 7 + 0.3x ƒ(x ) = 14 + 0.3x ƒ(x ) = 0.3(x + 2)
Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0
The cost to mail a 2-lb package is $7.
The cost to mail a 2-lb, 1 oz package is $7+$0.30(1).
That to mail a 2-lb, 2 oz package is $7+$0.30(2) = $7.60.

Following this pattern, the general formula is f(x) = $7 + $0.30x, where x represents the number of ounces OVER 2 lb.


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Consider this cube with a volume of 64 cubic centimeters.
Eduardwww [97]

Answer:

This is a perfect cube.

The side length is 4.

Taking the cube root of the volume will determine the side length.

Step-by-step explanation:

We are told that:

A cube has volume 64 centimeters cubed.

The formula for the volume of a cube = s³

Where s = side length

Hence

64 cm³ = s³

We can find s by finding the cube root of both sides

Hence,

cube root(64) = cube root(s³)

s = 4 cm

Note that 64 is a perfect cube because 4 × 4 × 4 = 4³ = 64 cm³

Therefore, it can be concluded of the cube that:

This is a perfect cube.

The side length is 4.

Taking the cube root of the volume will determine the side length.

3 0
3 years ago
How do you do this. Please give a full answer and explain why.
OverLord2011 [107]

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u>

\displaystyle \large{ {a}^{ - n}  =  \frac{1}{ {a}^{n} } }

Compare the terms.

\displaystyle \large{ {a}^{ - n}  =   {( - 2)}^{ - 3} }

Therefore, a = -2 and n = 3. From the law of exponent above, we receive:

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{ {( - 2)}^{ 3} } }

<u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>D</u><u>e</u><u>f</u><u>.</u> (For cubic)

\displaystyle \large{ {a}^{3}  = a \times a \times a }

Factor (-2)^3 out.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{( - 2) \times ( - 2) \times ( - 2)}}

(-2) • (-2) = 4 | Negative × Negative = Positive.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{4 \times ( - 2)}}

4 • (-2) = -8 | Negative Multiply Positive = Negative.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{  - 8}}

If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.

Hence,

\displaystyle \large \boxed{ {( - 2)}^{ - 3}  =  -  \frac{1}{  8}}

The answer is - 1 / 8

3 0
3 years ago
If p varies directly with q, and p = 10 when q = 5, what is the value of p when q = 20
Inessa [10]
The value of p would be 40. This is because the ratio of p:q = 10:5. this could be simplify into p:q = 2:1. Applying the ratio p:20 = 2:1, P=40.
8 0
3 years ago
Hereeeeeee helllllllpp lol
Ivenika [448]
It should be 0 because the only factor changing is the x value
7 0
3 years ago
Pls awnser asap!!!!!!!!!!!!!!!!!!!!!!!!!!!
dexar [7]

Answer:

0.875

Step-by-step explanation:

they're proportional.

7 0
3 years ago
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