PLEASE ANSWER WITH THE STEPS TO SOLVE THIS PROBLEM!

Plzz help....Calculate the length of the corresponding sides for FGHIJ and ABCDE. You will need to use the distance formula

GaryK [48]

Answer:

PLATO Explanation in the image below :)

5 0

3 years ago

Read 2 more answers

Look at bth plz help tysm

tangare [24]

Answer:

d

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

Please Help.....................................................

Anna71 [15]

There are 13 protons because the atomic number (the number in the top left corner) represents the number of protons. Then, to find the number of neutrons, you take the number of protons and subtract it from the atomic mass (the number on the bottom) when it is rounded. The number of electrons is the same as the protons when the atom is neutral

8 0

3 years ago

Solve for x in the equation x2-8x+41=0

Alinara [238K]

Answer:

d) 4 ± 5i

Step-by-step explanation:

Here we have to use the quadratic formula.

x = $\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}$